All categories

2 years ago

16−5a+2a−1=41−a what is a?

Mathematics

1 answer:

krek1111 [17]2 years ago

7 0

Answer:

a=-13

Step-by-step explanation:

16−5a+2a−1=41−a

16-1-41 = 5a-2a-a

-26 = 2a

a= -26/2

a=-13

You might be interested in

Triangle DEF is an isosceles, so AngleDEF Is-congruent-toAngleDFE. A horizontal line has points C, F, E, G. 2 lines extend from

asambeis [7]

Answer:

105 degrees

Step-by-step explanation:

Angle DEF measures 75°.Triangle DEF is an isosceles, so AngleDEF Is-congruent-toAngleDFE.

the angles all together is 180 degrees

so 180 - 75 = 105 degrees

3 0

2 years ago

Help Me Find The X Please

Papessa [141]

Answer:

x = 16

y = 16 sqrt(3)

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp/hyp

sin 60 = y/ 32

Multiply each side by 32

32 sin 60 = y

32 ( sqrt(3) /2) = y

16 sqrt(2)

cos theta = adj/ hyp

cos 60 = x /32

32 cos 60 = x

32 (1/2) =x

16 =x

4 0

2 years ago

Read 2 more answers

21.) A rectangle has an area of 36 square units. As the length and width change, what do you know about their

natima [27]

Answer:

the length and the width are inversely proportional to each other ( $l=\frac{36}{w}$ or $w=\frac{36}{l}$ )

Step-by-step explanation:

Let

l units = length of the rectangle,

w units = width of the rectangle.

The area of the rectangle is

$\text{Area}=\text{Length}\cdot \text{Width}$

A rectangle has an area of 36 square units, so

$l\cdot w=36$

Complete the table with some values of l and w that fit the previous formula:

$\begin{array}{ccc}\text{Length}&\text{Width}&\text{Area}\\ \\36&1&36\cdot 1=36\ un^2.\\18&2&18\cdot 2=36 \ un^2.\\12&3&12\cdot 3=36\ un^2.\\ 9&4&9\cdot 4=36\ un^2.\\l&w&l\cdot w=36 \ un^2.\end{array}$

As you can see, the length and the width are inversely proportional to each other ( $l=\frac{36}{w}$ or $w=\frac{36}{l}$ )

4 0

3 years ago

There are 200 students in the 8th grade class at Alleghany Middle School. Of these students, 8% play basketball and 14% play soc

sergeinik [125]

Answer:

The probability that a student plays either basketball or soccer is 19% or 0.19.

Step-by-step explanation:

Let A be the event that student play basketball and B be the event that student play soccer.

$P(A)=8\%$

$P(B)=14\%$

It is given that 6 students play on both teams.

$P(A\cap B)=\frac{6}{200}\times 100=3\%$

We have to find the probability that a student plays either basketball or soccer.

$P(A\cup B)=P(A)+P(B)-(A\cap B)$

$P(A\cup B)=8\%+14\%-3\%$

$P(A\cup B)=19\%$

Therefore the probability that a student plays either basketball or soccer is 19% or 0.19.

6 0

3 years ago

Plz help asap 25 points

Ierofanga [76]

Answer:

$14.39

Step-by-step explanation:

The formula for continuous compounding of interest is:

A = Pe^(rt), were P is the initial dollar amount, A is the final amount, r is the interest rate as a decimal fraction, and t is the time in years.

Here we have $2109 = $500e^(10r) and need to solve for r.

To do this, take the natural log of both sides, obtaining:

ln 2109 = ln 500+ 10r.

Then 10r = ln 2109 - ln 500, and

ln 2109 - ln 500

r = --------------------------------------------

= .1439

The interest rate was 14.39%.

8 0

2 years ago