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Annette [7]
2 years ago
13

TRUE/FALSE: The slope of the line that is PEREPNDICULAR to this line is -3/2.

Mathematics
1 answer:
chubhunter [2.5K]2 years ago
3 0

Answer:

True

Step-by Step Explanation:

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81 cubic feet are in 3 cubic yards.
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3 years ago
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Solve the equation and enter the value of x below.<br> x + 29 = 49<br> X =
andrew-mc [135]

Answer:

x = 20

Step-by-step explanation:

x + 29 = 49

- 29       - 29

x=20

5 0
3 years ago
PLEASE HELP!
ycow [4]

Answer:

I dont know what sin is

Step-by-step explanation:

3 0
3 years ago
Points A,B, and C form a triangle. Complete the statements to prove that the sum of the interior angles of ABC is 180 degrees
oee [108]

Answer:

Step-by-step explanation:

            Statements                                                       Reasons

1). Points A, B and C form the triangle           1). Given

2). Let DE be a line passing through             2). Definition of parallel lines

    B and parallel to AC

3). ∠3 ≅ ∠5 and ∠1 ≅ ∠4                                3). Theorem of Alternate

                                                                               interior angles  

4). m∠1 = m∠4 and m∠3 = m∠5                      4). Definition of alternate angles

5). m∠4 + m∠2+ m∠5 = 180°                           5). Angle addition and definition

                                                                             of straight lines

6). m∠1 + m∠2+ m∠3 = 180°                            6). Substitution

3 0
3 years ago
Let sin A= -3/5 with 270°&lt; A&lt; 360°. Find the following.<br> sin A/2
GREYUIT [131]

Answer:

1/sqrt10

Step-by-step explanation:

1) Find out cosA using formula (cosA)^2+(sinA)^2=1

The module of cosA= sqrt (1- (-3/5)^2)= sqrt 16/25=4/5

So cosA=-4/5 or cosA=4/5.

Due to the condition 270degrees< A<360 degrees, 0<cosA<1 that's why cosA=4/5.

2) Find sinA/2 using a formula cosA= 1-2sinA/2*sinA/2 where cosA=4/5.

(sinA/2)^2= 0.1

sinA= sqrt 0.1= 1/ sqrt10 or sinA= - sqrt 0.1= -1/sqrt10

But 270°< A< 360°, then 270/2°<A/2<360/2°

135°<A/2<180°, so sinA/2 must be positive and the only correct answer is

sin A/2= 1/sqrt10

6 0
3 years ago
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