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anzhelika [568]

3 years ago

12

A dartboard has 20 equally divided wedges, and you are awarded the number of points in the section your dart lands in. If you ar

e equally likely to land in any wedge, what is the probability you will score 5 points?

1 answer:

vesna_86 [32]3 years ago

5 0

Answer:

1/20

Step-by-step explanation:

There are 20 spots on the board and the odds u will land on 5 would be 1/20

You might be interested in

An equation of a hyperbola is given.

siniylev [52]

Answer:

a)

The vertices are $\left(3,\:0\right),\:\left(-3,\:0\right)$ .

The foci are $\left(3\sqrt{5},\:0\right),\:\left(-3\sqrt{5},\:0\right)$ .

The asymptotes are $y=2x,\:y=-2x$ .

b) The length of the transverse axis is 6.

c) See below.

Step-by-step explanation:

$\frac{\left(x-h\right)^2}{a^2}-\frac{\left(y-k\right)^2}{b^2}=1$ is the standard equation for a right-left facing hyperbola with center $\left(h,\:k\right)$ .

a)

The vertices $\:\left(h+a,\:k\right),\:\left(h-a,\:k\right)$ are the two bending points of the hyperbola with center $\:\left(h,\:k\right)$ and semi-axis a, b.

Therefore,

$\frac{x^2}{9}-\frac{y^2}{36}=1$ , is a right-left Hyperbola with $\:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6$ and vertices $\left(3,\:0\right),\:\left(-3,\:0\right)$ .

For a right-left facing hyperbola, the Foci (focus points) are defined as $\left(h+c,\:k\right),\:\left(h-c,\:k\right)$ where $c=\sqrt{a^2+b^2}$ is the distance from the center $\left(h,\:k\right)$ to a focus.

Therefore,

$\frac{x^2}{9}-\frac{y^2}{36}=1$ , is a right-left Hyperbola with $\:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6$ $c=\sqrt{3^2+6^2}= 3\sqrt{5}$ and foci $\left(3\sqrt{5},\:0\right),\:\left(-3\sqrt{5},\:0\right)$

The asymptotes are the lines the hyperbola tends to at $\pm \infty$ . For right-left hyperbola the asymptotes are: $y=\pm \frac{b}{a}\left(x-h\right)+k$

Therefore,

$\frac{x^2}{9}-\frac{y^2}{36}=1$ , is a right-left Hyperbola with $\:\left(h,\:k\right)=\left(0,\:0\right),\:a=3,\:b=6$ and asymptotes

$y=\frac{6}{3}\left(x-0\right)+0,\:\quad \:y=-\frac{6}{3}\left(x-0\right)+0\\y=2x,\:\quad \:y=-2x$

b) The length of the transverse axis is given by $2a$ . Therefore, the lenght is 6.

c) See below.

4 0

3 years ago

What is the solution for this equation? 3x - 1 = 5x - 11

Gennadij [26K]

3x - 1 = 5x - 11
Add 1 to both sides.
3x = 5x - 10
Subtract 5x from both sides.
-2x = -10
Divide by -2.

x = 5

3 0

3 years ago

Read 2 more answers

suppose S is between R and T. Use the segment addition postulate to solve for each variable. RS= 7y-4 , ST= y+5 , RT= 28

blagie [28]

RS+ST=RT

RS=7y-4

ST=y+5 using RS and RT in the first equation gives you:

7y-4+y+5=RT combine like terms on left side

8y+1=RT, and we are told that RT=28 so:

8y+1=28 subtract 1 from both sides

8y=27 divide both sides by 8

y=27/8

(RS=19 5/8, ST=8 3/8, RT=28)

6 0

3 years ago

A number y is no more than -8

Helen [10]

The answer to this is y <= -8.

6 0

3 years ago

Choose the correct ordering, from greatest to least, of the numbers below. L). 0.65 M) 640.23 N) 19.455 0) 6.682 P) 63.08

Neporo4naja [7]

Answer:

640.23. 63.08. 19.455. 6.682. 0.65

Step-by-step explanation:

if you look at the whole number you can see which is greater and which is less, if you still can't figure it out then, look at the tenths then hundredths and finally thousandths

6 0

3 years ago