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serg [7]
3 years ago
7

What type of model should be used to make a prediction from the given data? (0,3), (2,4), (5,5), (10,6)

Mathematics
1 answer:
mojhsa [17]3 years ago
5 0
I would say a Coordinate Grid.

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Find x<br>13+6+2x-18=4x-29​
Alla [95]

Answer:

x = 15

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Jack's mother gave him 50 chocolates to give to his friends at his birthday party. He gave 3 chocolates to each of his friends a
djverab [1.8K]

50 = 3x + 2

50 - 2 = 3x

48 = 3x

48/3 = 3x/3

16 = x


Jack has 16 friends.

4 0
3 years ago
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A clothing company plans to shear at least 700 sheep today all novices shear the same number of sheep per day and all experts sh
Llana [10]

Answer:

Each Novis share 7 sheep and each Expert share 12 sheep.

Step-by-step explanation:

Here, N represent the number of novices and E represent the number of experts needed for the company to meet its goal,

∵ All novices share the same number of sheep per day and all experts share the same number of sheep per day.

Let the sheep per day by a Novice = x and sheep per day by an expert = y,

So, the total sheep = xN + yE

According to the question,

Total sheep ≥ 700

⇒ xN + yE  ≥ 700,

By here, we have given the inequality for the given scenario,

7N+12E ≥ 700

By comparing,

x = 7 and y = 12

Hence, Each Novis share 7 sheep and each Expert share 12 sheep.

3 0
3 years ago
If (a-bi)^2 = 13 - 12i, what is the product of a and b?
VARVARA [1.3K]

Answer:

\large \boxed{\sf \ \ \ a\cdot b= 6 \ \ \ }

Step-by-step explanation:

Hello,

(a-bi)^2 = 13 - 12i\\\\ a^2+(bi)^2-2abi = 13-12i\\\\a^2-b^2-2abi=13-12i

Imaginary term must be the same so

-2ab=-12

2ab = 12

ab = 12/2 = 6

So the product of a and b is 6

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0
3 years ago
How to do substitution or elimination
Levart [38]
I: y=(1/2)x+5
II: y=(-3/2)x-7

substitution:
fancy word for insert the definition of one variable in one equation into the other
-> isolate a variable, luckily y is isolated (even in both equations) already
-> substitute y of II into I (=copy right side of II and replace y in I with it):

(-3/2)x-7=(1/2)x+5
-3x-14=x+10
-3x-24=x
-24=4x
-6=x

-> insert x back into I (or II):
y=(1/2)x+5
=(1/2)*(-6)+5
=-3+5=2

elimination: subtract one equation from the other to eliminate a variable, again y is already isolated->no extra work required

I-II:
y-y=(1/2)x+5-[(-3/2)x-7]
0=(1/2)x+5+(3/2)x+7
0=(4/2)x+12
-12=2x
-6=x

-> insert x back into I (or II):
y=(1/2)x+5
=(1/2)*(-6)+5
=-3+5=2
8 0
3 years ago
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