All categories

3 years ago

X squared + kx + 9 = (x + 3) sqaured

Mathematics

2 answers:

Masteriza [31]3 years ago

8 0

$x^2+kx+9=(x+3)^2\\\\x^2+kx+9=x^2+6x+9\\\\k=6$

Usimov [2.4K]3 years ago

3 0

The answer is 6 because with your use the exponent youll get x^3 + 6x + 9. So the x^2 and the 9 cancel out from bothside and you you are left with kx = 6x. Now divide by x and get k = 6.

You might be interested in

Which country is in D3?

Nikitich [7]

Answer:

$1.b \\ 2. c\\ 3. c\\ 4. a\\ 5. b\\$

Step-by-step explanation:

8 0

2 years ago

1) reflection across y = x<br> y<br> W<br> U<br> х

Romashka-Z-Leto [24]

Step-by-step explanation:

︻╦デ╤━╼︻╦デ╤━╼︻╦デ╤━╼︻╦デ╤━╼︻╦デ╤━╼︻╦デ╤━╼︻╦デ╤━╼

6 0

4 years ago

I need help can yall help me

Licemer1 [7]

Answer:

2{ $\frac{1}2}$ t+3}=1

2 $\frac{1}{2}$ t+2 * 3=1

t+6=1

t=-5

Step-by-step explanation:

2{ $\frac{1}2}$ t+3}=1

2 $\frac{1}{2}$ t+2 * 3=1

t+6=1

t=-5

6 0

3 years ago

Can I have some help

Wewaii [24]

Answer:

1/8miles a second it's easy I'm good at mathematics

8 0

3 years ago

A shipping company devises a messaging consisting of 9 flags hung in a line. Howmany different messages are possible if communic

Feliz [49]

Answer: 1260

Step-by-step explanation:

The number of permutation of n things in which 'a' things are like , 'b' things are like and so on.. is given by :-

$\dfrac{n!}{a!\ b!....}$

Given : A shipping company devises a messaging consisting of 9 flags hung in a line.

Then, the number of different possible messages constructed from a set of 4 white, 3 red, and 2 blue flags will be :-

$\dfrac{9!}{4! 3!2!}\\\\=\dfrac{9\times8\times7\times6\times5\times4!}{4! 3\times2\times2}\\\\=1260$

Hence, the number of different possible messages constructed from a set of 4 white, 3 red, and 2 blue flags= 1260

8 0

4 years ago