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SCORPION-xisa [38]
3 years ago
6

Adante begins to evaluate the expression 3 and one-third times 5 and one-fourth using the steps below. 3 and one-third times 5 a

nd one-fourth 3 and one-third times (5 + one-fourth) (3 and one-third times 5) + (3 and one-third times one-fourth) (3 + one-third) (5) + (3 + one-third) (one-fourth) Which could be his next step? (3) (5) + (one-third) (5) + (3) (one-fourth) + (one-third) (one-fourth) (3) (5) + (3) (one-third) + (3) (one-fourth) + (3) (one-third) (3 and one-third) (3 and one-third) + (5) (one-fourth) (3 and one-third + 3 and one-third) times (5 + one-fourth)
Mathematics
2 answers:
xxTIMURxx [149]3 years ago
8 0

Answer:

a

Step-by-step explanation:

ella [17]3 years ago
6 0

Answer:

a

Step-by-step explanation:

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Please help quicklyyy!!!
Fiesta28 [93]

Answer:

Its the 3 one

Step-by-step explanation:

7 0
3 years ago
Simplify<br><br> -6 + { 14 + { 60 - 9 ( 1 + 3 ) { }
Lelu [443]

Answer:

32

Step-by-step explanation:

−6+14+60−9(1+3)

=32

4 0
2 years ago
Solve for x and y 100x + 50y = 200
Eva8 [605]

Answer:

x = 1 and y = 2

Step-by-step explanation:

because 100(1) + 50(2) = 100 + 100 = 200


8 0
3 years ago
1/1-cos theta + 1/1+cos theta = 2cosec² theta​
BARSIC [14]

Answer:

Step-by-step explanation:

8 0
3 years ago
WILL GIVE A BRAINLEST!!!!!!
Andrej [43]
We have that
<span>(c-4)/(c-2)=(c-2)/(c+2) - 1/(2-c)
 </span>- 1/(2-c)=-1/-(c-2)=1/(c-2)

(c-4)/(c-2)=(c-2)/(c+2)+ 1/(c-2)------- > (c-4)/(c-2)-1/(c-2)=(c-2)/(c+2) 
(c-4-1)/(c-2)=(c-2)/(c+2)---------------- > (c-5)/(c-2)=(c-2)/(c+2)

(c-5)/(c-2)=(c-2)/(c+2)------------- > remember (before simplifying) for the solution that c can not be 2 or -2
(c-5)*(c+2)=(c-2)*(c-2)------------------ > c²+2c-5c-10=c²-4c+4
-3c-10=-4c+4----------------------------- > -3c+4c=4+10----------- > c=14

the solution is c=14
 
the domain of the function is (-∞,-2) U (-2,2) U (2,∞) or 
<span>all real numbers except c=-2 and c=2</span>


5 0
3 years ago
Read 2 more answers
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