Given:
6 . ln x = 9.1
We are asked to find the solution of the above equation leaving the answer to two decimal places.
6lnx = 9.1
Let's divide both sides by 6
6linx/6 = 9.1/6
6 cancelling out on the left hand side.
lnx = 9.1/6
linx = 1.5166
x = e^1.5166
x = 4.5570
x = 4.56 (to two decimal places).
The correct option is A, which is x = 4.56
You work out 500-82=418
Next you do 300-61=239
Finally you add 239+412=657
Answer:
67,200,000 pounds
Step-by-step explanation:
Base dimension is incomplete , lets assume it to be 50yd by 120yd
so, The pyramid has a rectangular base that measures 50 yd by 120 yd
In order to find weigh, first lets find out the volume of pyramid
the volume of a pyramid is determined by
V = 1/3 Bh
where B is the area of the base.
V = 1/3(120)(50)(70) =
V=140000 cubic yards
next is to determine weight
As you know, D = M/V is given as 480 lbs/cubic yard
so the weight (mass) is
:
W = VD = 140000 x 480 = 67,200,000 pounds
Thus, the pyramid weigh 67,200,000 pounds
Answer:
0.45 ft/min
Step-by-step explanation:
Given:-
- The flow rate of the gravel,
- The base diameter ( d ) of cone = x
- The height ( h ) of cone = x
Find:-
How fast is the height of the pile increasing when the pile is 10 ft high?
Solution:-
- The constant flow rate of gravel dumped onto the conveyor belt is given to be 35 ft^3 / min.
- The gravel pile up into a heap of a conical shape such that base diameter ( d ) and the height ( h ) always remain the same. That is these parameter increase at the same rate.
- We develop a function of volume ( V ) of the heap piled up on conveyor belt in a conical shape as follows:
- Now we know that the volume ( V ) is a function of its base diameter and height ( x ). Where x is an implicit function of time ( t ). We will develop a rate of change expression of the volume of gravel piled as follows Use the chain rule of ordinary derivatives:
- Determine the rate of change of height ( h ) using the relation developed above when height is 10 ft: