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3 years ago

Write an exponential function that passes through the points (0, 3) and (-1, 6)

1 answer:

3 0

Standard form of an exponential function is y=ab^x
when x=0, y=3, 3=ab^0, so you can figure out that a=3
when x=-1, y=6, 6=3b^(-1), b^(-1)=2, b=1/2
so the equation is y=3(1/2)^x

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Answer as soon as possible

alexandr1967 [171]

Answer:

C −2a^3+9a^2+45a+6ab^2+18b^2

Step-by-step explanation:

(a+3) ( −2a^2+15a+6b^2)

Distribute the a to the large term in parentheses and the 3 to the large term in parentheses

a ( −2a^2+15a+6b^2)+3 ( −2a^2+15a+6b^2)

−2a^3+15a^2+6ab^2 −6a^2+45a+18b^2

Combine like terms

−2a^3+15a^2−6a^2+6ab^2 +45a+18b^2

-2 a^3 + 9 a^2 + 6 a b^2 + 45 a + 18 b^2

3 0

3 years ago

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HELP PLEASEE!!!!

ss7ja [257]

Answer:

See below ~

Step-by-step explanation:

$\textsf {Each of the steps has been reasoned below :}$

$\implies \textsf {3x - 2 = 4 (Given)}$

$\implies \textsf {3x = 6 (Addition Property of Equality)}$

$\implies \textsf {x = 2 (Division Property of Equality)}$

$\textsf {In the second step, the property has been applied}\\\textsf {by adding 2 to each side of the equation.}$

$\textsf {In the third step, the property has been applied by dividing 3 on each side.}$

3 0

2 years ago

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Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (

Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

$P(\frac{T}{S}) = 0.95$

$P(\frac{T}{S^c}) = 0.05$

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

$P(S^c) = 1 - P(S)$

= 1 - 0.3

= 0.7

ii. $P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}$

$= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }$

$= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}$

= 0.8906

iii. $P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}$

$= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }$

$= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}$

= 0.0221

We simply applied the above formulas so that the each part could come

8 0

3 years ago

Using the x intercept method what are all the real solutions of the equation x^3-8x^2+9x+18=0

Paul [167]

Give me an idea of what you think?

7 0

3 years ago

Subtraia do quadrado de 3/4,o cubo de 1/2.que resultado encontrara

vova2212 [387]

A resposta para esta equação é 7/16.

5 0

3 years ago

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