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Flura [38]
3 years ago
5

match the transformation with the basic elementary word used to describe the transformation? PLEASE HURRY 10 POINTS!!!!​

Mathematics
1 answer:
kolbaska11 [484]3 years ago
3 0

Answer:

flip to 2 _slide to 3_ turn to 1

Step-by-step explanation:

lucky math

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Substances that are made of just one kind of atom are ____ .
makvit [3.9K]
Elements, they’re a pure substance and can’t be broken down into simpler substances.
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3 years ago
Can someone help me with this? I need it done but I'm not able to figure it out.
kati45 [8]

Answer:

A

Step-by-step explanation:

The y's line is vertical and is the second number in an order pair

5 0
3 years ago
John is 1.7 meters tall and ken is 1.5 meters tall. what is the difference in their heights, expressed in centimeters? A.0.2cm B
Leona [35]
Let's go ahead and find the difference in height in meters.

1.7-1.5= 0.2 meters

There are 100 centimeters in a meter.

0.2*100= 20

The correct answer is "C". 20 cm.

I hope this helps!
~kaikers
6 0
4 years ago
An investment earn 6% simple interest. What amount of principal is need to have $3000 after 5 years
irakobra [83]

Answer:

The amount of $1000 principal is needed to have $3000 after 5 years.

Step-by-step explanation:

As the interest formula is

I=Prt

Where

  • P is the principle
  • r is the rate in decimal
  • t is the time in years

Substituting the following values in the interest formula and solve for P

I=$3000

r = 6% = 6/100 = 0.06

t = 5

so the equation becomes

I=Prt

3000=P\left(0.06\right)\left(5\right)

switch both sides

P\left(0.06\right)\left(5\right)=3000

P\left(0.3\right)=3000

P=10000 $

Therefore, the amount of $1000 principal is needed to have $3000 after 5 years.

6 0
3 years ago
Calculate the sample standard deviation and sample variance for the following frequency distribution of heart rates for a sample
adelina 88 [10]

Answer:

\sigma = 12.5 ---- sample standard deviation

\sigma^2 = 157.2 ---- sample variance

Step-by-step explanation:

Solving (a): The sample variance

First, we calculate the midpoint of each class (this is the average of the limits)

So, we have:

x_1 = \frac{56 + 64}{2} = 60

x_2 = \frac{65 + 73}{2} = 69

And so on

So, the table becomes:

\begin{array}{cc}{x} & {f} & {60} & {11} & {69} & {15} & {78} & {14} & {87} & {4} & {96} & 11 \ \end{array}

Calculate the mean

\bar x = \frac{\sum fx}{\sum f}

\bar x = \frac{60*11+69*15+78*14+87*4+96*11}{11+15+14+4+11}

\bar x = \frac{4191}{55}

\bar x = 76.2

The variance is:

\sigma^2 = \frac{\sum f(x - \bar x)^2}{\sum f - 1}

So, we have:

\sigma^2 = \frac{(60 - 76.2)^2*11+(69 - 76.2)^2*15+(78 - 76.2)^2 *14+(87 - 76.2)^2*4+(96 - 76.2)^2*11}{11+15+14+4+11-1}

\sigma^2 = \frac{8488.8}{54}

\sigma^2 = 157.2

The sample standard deviation is:

\sigma = \sqrt{\sigma^2

\sigma = \sqrt{157.2

\sigma = 12.5

Solving (b): The sample variance

In (a), we calculate the sample variance to be:

\sigma^2 = 157.2

6 0
3 years ago
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