All categories

3 years ago

3. Jalen is a lifeguard at a public swimming pool and is planning to string

Mathematics

1 answer:

m_a_m_a [10]3 years ago

7 0

Answer:

$Flag = 55.90m$

Step-by-step explanation:

Given

$Length = 50m$

$Width = 25m$

Required

Determine the length of the flag

Because the flag crosses through opposite diagonals of the pool. Its length is the length of the diagonal of the pool.

This is calculated using Pythagoras theorem.

$Flag^2 = Length^2 + Width^2$

Substitute values for Length and Width

$Flag^2 = 50^2 + 25^2$

$Flag^2 = 2500 + 625$

$Flag^2 = 3125$

Take positive square root of both sides

$Flag = \sqrt{3125$

$Flag = 55.90m$

<em>Hence, the length of the flag is approximately 55.90m</em>

You might be interested in

(x3 - 2x² - 1) + (x - 1)

SSSSS [86.1K]

Answer:

x^3 -2x^2 -1 + (x-1)

= x^3 -2x^2 + x -2

= (x-2)(x^2+1)

Hope this helps!

5 0

3 years ago

Twelve of the 40 cars pulled by the locomotive were tankers.

quester [9]

12 are tankesr
40 cars total
12/40
12/40=6/20=3/10

3/10=tankders
10/10-3/10=7/10
7/10=70/100=70%
70% wern't tankser

3 0

3 years ago

What is the equation of the line perpendicular to 3x+y= -8that passes through -3,1? Write your answer in slope-intercept form. S

Gekata [30.6K]

Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is $y=\frac{1}{3} x+2$

<u>Solution:</u>

Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).

Generic slope intercept form of a line is given by y = mx + c

where m = slope of the line.

Let's first find slope intercept form of 3x + y = -8

3x + y = -8

=> y = -3x - 8

On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3

And as the line passing through (-3,1) and is perpendicular to 3x + y = -8, product of slopes of two line will be -1 as lies are perpendicular.

Let required slope = x

$\begin{array}{l}{=x \times-3=-1} \\\\ {=>x=\frac{-1}{-3}=\frac{1}{3}}\end{array}$

So we need to find the equation of a line whose slope is $\frac{1}{3}$ and passing through (-3,1)

Equation of line passing through $(x_1 , y_1)$ and having lope of m is given by

$\left(y-y_{1}\right)=\mathrm{m}\left(x-x_{1}\right)$

$\text { In our case } x_{1}=-3 \text { and } y_{1}=1 \text { and } \mathrm{m}=\frac{1}{3}$

Substituting the values we get,

$\begin{array}{l}{(\mathrm{y}-1)=\frac{1}{3}(\mathrm{x}-(-3))} \\\\ {=>\mathrm{y}-1=\frac{1}{3} \mathrm{x}+1} \\\\ {=>\mathrm{y}=\frac{1}{3} \mathrm{x}+2}\end{array}$

Hence the required equation of line is found using slope intercept form

4 0

3 years ago

In a lab, a substance was cooked by 42 C over a period of 7 hours at a constant rate. What was the change in temperature each ho

Mekhanik [1.2K]

Given that we have the change in temperature over 7 hours and we are looking for the change over 1 hour, we can divide the total change in temperature by 7. Thus, the change in temperature would be $\frac{42}{7} C^{\circ}$ .