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Vikki [24]
3 years ago
11

3. Jalen is a lifeguard at a public swimming pool and is planning to string

Mathematics
1 answer:
m_a_m_a [10]3 years ago
7 0

Answer:

Flag = 55.90m

Step-by-step explanation:

Given

Length = 50m

Width = 25m

Required

Determine the length of the flag

Because the flag crosses through opposite diagonals of the pool. Its length is the length of the diagonal of the pool.

This is calculated using Pythagoras theorem.

Flag^2 = Length^2 + Width^2

Substitute values for Length and Width

Flag^2 = 50^2 + 25^2

Flag^2 = 2500 + 625

Flag^2 = 3125

Take positive square root of both sides

Flag = \sqrt{3125

Flag = 55.90m

<em>Hence, the length of the flag is approximately 55.90m</em>

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Answer:

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(I am sure of the answer, I have completed the test.)


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Answer:

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Step-by-step explanation:

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Firlakuza [10]

Answer:

1st pic) 17.8

2nd pic) 16.8

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Step-by-step explanation:

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(write equation) Cos 27 (cos 27 = 0.89) = \frac{x}{20}

(new equation) 0. 89 = \frac{x}{20}

(multiply 20 on both sides) 0.89 x 20 = \frac{x}{20} x 20

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<u>2nd pic:</u> tan = \frac{adjacentx}{hypothenuse}

(write equation) tan 40 (tan 40 = 0.84) = \frac{32}{x}

(new equation) 0.84 =  \frac{32}{x}

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<u>3rd pic:</u> cos = \frac{adjacent}{hypothenuse}

(write equation) cos 55 (cos 55 = 0.57) = \frac{16}{x}

(new equation) 0.57 = \frac{16}{x}

(multiply 16 on both sides) 0.57 x 16 = \frac{16}{x} x 16

(solve) 9.1 = x

<u>4th pic:</u> tan = \frac{adjacentx}{hypothenuse}

(write eqaution) tan 42 (tan 42 = 0.90) = \frac{x}{15}

(new equation) 0.90 = \frac{x}{15}

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3 years ago
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Answer:

I'm not sure, but I'll try

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