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nika2105 [10]
3 years ago
15

How does the product 110×any number compare to the product 11× any number

Mathematics
1 answer:
Effectus [21]3 years ago
6 0
The product of 100 x a number would be 10 times larger than the product of 11 x a number
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9.0 - 0.178=<br>5 points<br>Your answer​
bagirrra123 [75]

Answer:

8.822. Hope this helps.

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4 years ago
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What's the simplified radical of √26?
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A hotel has a pool in the shape of a rectangle. The pool is 8 m long, 3 m wide, and 2,000 cm deep. What is the volume of the poo
Maslowich
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There are 28 total students in Mr. Flynn’s class. The ratio of his students who are in the play to those who are not in the play
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3 years ago
Analysis of an accident scene indicates a car was traveling at a velocity of 69.5 mph (31.1 m/s) along the positive x-axis at th
STatiana [176]

We can find the acceleration via

{v_f}^2-{v_i}^2=2a\Delta x

We have

\left(5.20\dfrac{\rm m}{\rm s}\right)^2-\left(31.1\dfrac{\rm m}{\rm s}\right)^2=2a(115\,\mathrm m)

\implies\boxed{a=-4.09\dfrac{\rm m}{\mathrm s^2}}

Then by definition of average acceleration,

a_{\rm ave}=\dfrac{v_f-v_i}t

so that

-4.09\dfrac{\rm m}{\mathrm s^2}=\dfrac{5.20\frac{\rm m}{\rm s}-31.1\frac{\rm m}{\rm s}}t

\implies\boxed{t=6.33\,\mathrm s}

We alternatively could have found the time without knowing the acceleration. Since acceleration is constant, the average velocity is

v_{\rm ave}=\dfrac{x_f-x_i}t=\dfrac{v_f+v_i}2

Then

\dfrac{115\,\rm m}t=\dfrac{5.20\frac{\rm m}{\rm s}+31.1\frac{\rm m}{\rm s}}2

\implies\boxed{t=6.33\,\mathrm s}

7 0
3 years ago
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