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Andre45 [30]
4 years ago
10

Evaluate n + 5/5 When n= -10

Mathematics
2 answers:
vesna_86 [32]4 years ago
3 0

Answer:

n + 5/5 = -9

Step-by-step explanation:

Neko [114]4 years ago
3 0

Answer:

see below

Step-by-step explanation:

If the problem is

(n+5) /5

Let n = -10

(-10+5)/5

-5/5

-1

or if

n+ 5/5

-10 + 1

-9

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Find the slope of each line x=1
vovangra [49]
The slope of the line <span>x=1</span><span> does not exist. Because there are no tow points with different </span>x<span> values on the line.</span>
It is not defined.
<span>This case is not includes in the definition of slope.</span>
3 0
3 years ago
Stuck in it from a week!!<br> Help please.
nadya68 [22]
The answer is 49 because x = 1/7 and 1/7^-2 =49
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An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the
MrRa [10]

your question is incomplete, here you can find the complete question below:

An angles vertex is located at (0,0) and the initial ray of the angle points in the 3 oclock direction. Let theta represent the varying radian measure of the angle.

a. if the terminal ray of the angle passes through the point(3.38,2.32), whta is the slope of the terminal ray of the angle?

b. if the terminal ray of the angle passes through the point(1.49,3.82), whta is the slope of the terminal ray of the angle?

c. if the terminal ray of the angle passes through the point(1.1,3.95), what is the slope of the terminal ray of the angle?

Answer:

a. 1.45

b. 2.56

c. 3.59

Step-by-step explanation:

As we know that formula to find the slope is change in y-coordinates divided by change in x-coordinates.

slope=\frac{chnage\ in\ y}{chnage\ in\ x}=\frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

It is given that initial point is (x1,y1)=(0,0)

Part(a)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(3.38,2.32)

so the slope of the terminal ray is

slope=\frac{3.38-0}{2.32-0}=\frac{3.38}{2.32}=  1.45

Part(b)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.49,3.82)

so the slope of the terminal ray is

slope=\frac{3.82-0}{1.49-0}=\frac{3.82}{1.49}=2.56

Part(c)

initial point is (x1,y1)=(0,0)

terminal point is (x2,y2)=(1.1,3.95)

so the slope of the terminal ray is

slpoe=\frac{3.95-0}{1.1-0}=\frac{3.95}{1.1}=  3.59

6 0
3 years ago
In triangle def the measure of angle F=90 degrees fe=21 df=20cand ed=29 what is the cosine of angle e to nearest hundredth
Fudgin [204]

Answer:

four angles at point B in this second diagram.

Step-by-step explanation:

7 0
3 years ago
Help please I really do need help
LuckyWell [14K]

Answer:

  P'(-6, -4)

Step-by-step explanation:

The (x, y) coordinates of the plotted point P are (-2, 2).

Putting those values into the translation formula, you get ...

  (x, y) ⇒ (x -4, y -6)

  (-2, 2) ⇒ (-2 -4, 2 -6) = (-6, -4)

The coordinates of the translated point P' are ...

  P'(-6, -4)

4 0
3 years ago
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