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3 years ago

What is the product of the binomials below? (5x + 2)(4x +4)

Mathematics

2 answers:

never [62]3 years ago

7 0

Answer:

20x^2 + 28x + 8

Step-by-step explanation:

you use the box method shown in the picture to multiply then combine like terms

mestny [16]3 years ago

4 0

You can use the FOIL method (First, Outer, Inner Last) as how most people prefer it.

5x*4x=20x^2

5x*4=20x

2*4x=8x

2*4=8

Combine them all together and you get 20x^2 + 28x +8

I hope this helps.

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Assume Earth and a cloud layer 770 m above the Earth can be treated as plates of a parallel-plate capacitor.

Travka [436]

Answer:

(a) 1.15×10⁻⁸ F.

(b) 1.5×10⁻⁸ C.

Step-by-step explanation:

(a)

Capacitance of a capacitor: This is the ability for a capacitor to store charge.

The S.I unit of capacitance of a capacitor is Farad (F).

Mathematically, it is represented as

C = ε₀A/d² ................. Equation 1

Where C = Capacitance of the capacitor, ε₀ = permitivity of free space, A = area of the plates, d = distance between the plates.

Given: A = 1×10⁶ m². d = 770 m

Constant: ε₀ = 8.85×10⁻¹² F/m

Substituting these values into equation 1

C = 8.85×10⁻¹²(1×10⁶ )/770

C = 8.85×10⁻⁶/770

C= 0.0115×10⁻⁶

C = 1.15×10⁻⁸ F.

Thus the capacitance of the cloud layer = 1.15×10⁻⁸ F.

(b)

Electric Field Strength: This is the force per unit charge which is exerted at a point in a in a electric field.

It can be represented mathematically as

E = kq/d²........................... Equation 2

Where E = Electric Field Strength, q = charge, d = distance. k = proportionality constant.

Making q the subject of the equation above,

q = Ed²/k ........................... Equation 3.

Given: E = 2×10⁶ N/C, d = 770 m

Constant: k = 1/4πε₀ = 9×10⁹ Nm²/C²

Substituting these values into equation 3

q = 2×10⁶(770)²/(9×10⁹)

q = (2×10⁶)(592900)/(81×10¹⁸)

q = 14639.5×10⁻¹²

q ≈ 1.5×10⁻⁸ C.

Thus the charge the cloud can hold = 1.5×10⁻⁸ C.

3 0

4 years ago

What is the distance around a triangle that has measuring 2 1/8 feet,3 1/2 feet, 2 1/2 feet

N76 [4]

Perimeter: 2 1/8 + 3 1/2 + 2 1/2 = 7 (1 + 4 + 4)/8 = 7 9/8 = 8 1/8

Hope this will help you!

3 0

3 years ago

What is the height of a pyramid (with a square base) whose side length is 12 cm and its slant

Bingel [31]

We have been given that side length of pyramid the square base is 12 cm and its slant height is 10 cm. We are asked to find the height of the pyramid.

We will use slant height of a pyramid formula to solve our given problem.

$s=\sqrt{h^2+\frac{1}{4}a^2}$ ,where,

s = Slant height,

h = Height,

a = Each side of square base.

Upon substituting our given values in above formula, we will get:

$10=\sqrt{h^2+\frac{1}{4}\cdot 12^2}$

$10=\sqrt{h^2+\frac{1}{4}\cdot 144}$

$10=\sqrt{h^2+36}$

Switch sides:

$\sqrt{h^2+36}=10$

Let us square both sides:

$(\sqrt{h^2+36})^2=10^2$

$h^2+36=100$

$h^2+36-36=100-36$

$h^2=64$

Now we will take positive square root of both sides.

$\sqrt{h^2}=\sqrt{64}$

$h=8$

Therefore, the height of the pyramid is 8 cm and option 'b' is the correct choice.

7 0

3 years ago

On Monday, jack and Jill walked from their house up the hill to get to the bus stop. They walked 4 yards every three seconds. Wr

never [62]

Answer: Our required equation will be

$3d=4t$

Step-by-step explanation:

Since we have given that

Jack and Jill walked 4 yards every three seconds

As we know that

$Speed=\frac{Distance}{Time}\\\\Speed=\frac{4}{3}\text{ yards per seconds}\\$

Now, we need to find the find the equation to represent the distance,<em>d</em>,

Jack and Jill walked over time <em>t </em>.

So here it is,

$Distance=Speed\times Time\\\\d=\frac{4}{3}\times t\\\\d=\frac{4}{3}t\\\\3d=4t$

Hence, our required equation will be

$3d=4t$

4 0

3 years ago

later reflected parallelogram abcd across the y-axis. if angle a is 115° and angle b is 65°, what is the degree measurement of a

GaryK [48]

A reflection will not change the measurement of the angle.
Angle a will still be 115 degrees.

6 0

3 years ago