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Harman [31]
2 years ago
10

[BrO- ]initial is 0.56 M. 33 seconds later [BrO- ] is 0.14 M. What is the rate of change of [BrO- ] in M/s? (The brackets, [ ],

indicate concentration, that is, molarity (M) or moles/liter.)
Chemistry
2 answers:
iVinArrow [24]2 years ago
3 0

Answer:

0.013 M/s

Explanation:

Given data

  • Initial concentration of BrO⁻: 0.56 M
  • Final concentration of BrO⁻: 0.14 M
  • Time (t): 33 s

Since the final concentration of BrO⁻ is lower than the initial concentration of BrO⁻, BrO⁻ is dissapearing. The rate of dissapearance of BrO⁻ is:

rBrO⁻ = - Δ [BrO⁻] / t

rBrO⁻ = - (0.14 M - 0.56 M)/ 33 s

rBrO⁻ = 0.013 M/s

grigory [225]2 years ago
3 0

Answer:

0.013 M/s

Explanation:

Initial concentration of BrO⁻: 0.56 M

Final concentration of BrO⁻: 0.14 M

Time (t): 33 s

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Natasha_Volkova [10]

Answer:

3.13%.

Explanation:

The following data were obtained from the question:

Original amount (N₀) = 0.15

Half life (t½) = 2 mins

Number of half-life (n) = 5

Fraction of sample remaining =.?

Next, we shall determine the amount remaining (N) after 5 half-life. This can be obtained as follow:

Amount remaining (N) = 1/2ⁿ × original amount (N₀)

NOTE: n is the number of half-life.

N = 1/2ⁿ × N₀

N = 1/2⁵ × 0.15

N = 1/32 × 0.15

N = 0.15/32

N = 4.69×10¯³

Therefore, 4.69×10¯³ is remaining after 5 half-life.

Finally, we shall the fraction of the sample remaining after 5 half-life as follow:

Original amount (N₀) = 0.15

Amount remaining (N) = 4.69×10¯³

Fraction remaining = N/N₀ × 100

Fraction remaining = 4.69×10¯³/0.15 × 100

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3 0
2 years ago
10. Write the word equation of the following skeleton equation.
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4 0
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1 mole = 6.022 × 10²³  atoms of Al

8.28 mol×6.022 × 10²³  atoms / 1mol

49.86 × 10²³  atoms of Al

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3 years ago
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