Answer:
- <em>Chemical equations are balanced </em><u>to comply with the law of conservation of mass.</u>
Explanation:
Law of conservation of mass states that matter cannot be either created or destroyed.
A skeleton chemical equation shows the reactants and products of a chemical reaction without taking into account the real proportion in which the reactants combine and the products are obtained.
An example of a skeleton reaction is the combustion of methane:
Such as that equation is shown, there are four atoms of hydrogen in the reactants but only 2 atoms of hydrogen in the products. Also, there are 2 atoms of oxygen in the reactants but three atoms of oxygen in the products. This seems to show that some atoms of hydrogen have been destroyed and some atoms of oxygen have been created. This is impossible as it is against the law of conservation of matter.
Then, to show a real situation, the chemical equation of combustion must be balanced, adjusting the coefficients. This is the balanced chemical equation:
Now you see that the number of atoms of each matter is conserved: the number of carbon atoms in each side is 1, the number of atoms of hydrogen in each side is 4, and the number of atoms of oxygen in each side is 4. Thus, by balancing the chemical equation, the law of conservation of mass is not violated.
Answer:
0.1 is the retention factor.
Explanation:
Distance covered by solvent ,
Distance covered by solute or ion,
Retention factor
is defined as ratio of distance traveled by solute to the distance traveled by solvent.
0.1 is the retention factor.
Answer:
C. copper.
Explanation:
- The atom which loses electrons (its oxidation sate be more positive) is the atom that is oxidized.
- While, the atom which gains electrons (its oxidation sate be more negative) is the atom that is reduced.
It is oxidation sate is changed from (+5) in the reactants (NO₃⁻) to (+4) in the products (NO₂). N gains 1 electron
So, it is reduced.
It is oxidation sate is the same (-2) in the reactants (NO₃⁻) and (-2) in the products (NO₂).
<em>So, it is neither be oxidized nor reduced.</em>
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It is oxidation sate is changed (0) in the reactants (Cu) to (+2) in the products (Cu²⁺). Cu loses 2 electrons.
<em>So, it is oxidized.</em>
<em></em>
It is oxidation sate is the same (+1) in the reactants (H⁺) and (+1) in the products (H₂O).
<em>So, it is neither be oxidized nor reduced.</em>
<em></em>
moles of excess reactant remaining: 0.67 mol CS2
moles of each product formed: 0.33 mol CO2 and 0.67 mol SO2
your coefficients in the chemical equation reveal the molar ratio of the reactants that must be present to give a complete reaction of both reactants. in this case each mole of CS2 requires 3 moles of O2 to form the products given. if you start with equimolar amounts of both reactants then the O2 must be in insufficient supply to completely react with all of the CS2. if only 1 mole of O2 is present, it will be consumed by one third that amount of CS2. all O2 will react. 0.67 mole of CS2 will remain. the CO2 comes from the carbon in CS2, so 0.33 mole of CO2 will be produced. since 2 moles of SO2 are produced for each mole of CO2 produced, then the amount of SO2 produced will be 0.67 mol.
Answer:
An if/then statement. If ____happens, then _____ happens.
Explanation:
