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SVETLANKA909090 [29]
3 years ago
6

Question

Chemistry
1 answer:
kap26 [50]3 years ago
5 0

The statements which correctly describe the Cl-Cl bond is:

It is a sigma bond.

It is formed by overlap of two hybrid orbitals.

Explanation:

The 2 atoms of the chlorine atom are bonded by single bond by sharing of electrons as chlorine has 7 electrons in its outer shell.

1s22s2p63s23p5 configuration of each atom

A covalent bond is formed between the two chlorine atoms.

The electrons are shared by molecular orbitals by overlapping the orbital as each of the chlorine atom will try to complete its octet. The electrons from p orbitals are shared hence sigma bond.

There is no hybridization in Cl2 it only has only overlapping of electrons in p orbitals.

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Question 8 of 8> 0 Attempt 2 A chemist needs to determine the concentration of a sulfuric acid solution by titration with a s
Nesterboy [21]

Answer:

12.29 M

Explanation:

  • The reaction that takes place is:

H₂SO₄ + 2NaOH → 2Na⁺ + SO₄⁻² + 2H₂O

  • Now let's calculate the <u>moles of H₂SO₄ that were titrated</u>:

0.1284 M * 0.1915L*\frac{1molAcid}{2molNaOH} = 0.01229 mol H₂SO₄.

  • Thus, the <u>concentration of the diluted solution is</u>:

0.01229 mol H₂SO₄ / 0.010 L = 1.229 M

  • Finally, the <u>concentration of the original acid solution is:</u>

1.229 M*\frac{250mL}{25mL} = 12.29 M

5 0
3 years ago
How many moles of carbon, hydrogen, and oxygen are present in a 100-g sample of ascorbic acid?
Y_Kistochka [10]

There are:

3.41 moles of C

4.54 moles of H

3.40 moles of O.

Why?

To solve the problem, the first thing that we need to do is to write the chemical formula of the ascorbic acid.

C_{6}H_{8}O_{6}

Now, we know that there are 100 grams of the compound, so, the masses of each element will represent the percent in the compound.

We have that:

C_{6}=12.0107g*6=72.08g\\\\H_{8}=1.008g*8=8.064g\\\\O_{6}=15.999g*6=95.994g\\\\C_{6}H_{8}O_{6}=72.08g+8.064g+95.994g=176.138g

To know the percent of each element, we need to to the following:

C=\frac{72.08g}{176.138g}*100=0.409*100=40.92(percent)\\\\H=\frac{8.064g}{176.138g}*100=4.58(percent)\\\\O=\frac{95.994}{176.138g}*100=54.49(percent)

So, we know that for the 100 grams of the compound, there are:

40.92 grams of C

4.58 grams of H

54.49 grams of O

We know the molecular masses of each element:

C=12.0107\frac{g}{mol}\\\\H=1.008\frac{g}{mol}\\\\O=15.999\frac{g}{mol}{mol}

Now, to calculate the number of moles of each element, we need to divide the mass of each element by the molecular mass of each element:

C=\frac{40.92g}{12.010\frac{g}{mol}}=3.41mol\\\\H=\frac{4.58g}{1.008\frac{g}{mol}}=4.54mol\\\\O=\frac{54.49g}{15.999\frac{g}{mol}}=3.40mol

Hence, we have that there are 3.41 moles of C, 4.54 moles of H, and 3.40 moles of O.

Have a nice day!

5 0
3 years ago
A compound containing Na, C, and O is found to have 1.06 mol Na, 0.528 mol C, and 1.59 mol O. What is the empirical formula of t
Effectus [21]

Given :

Moles of Na : 1.06

Moles of C : 0.528

Moles of O : 1.59

To Find :

The empirical formula of the compound.

Solution :

Dividing moles of each atom with the smallest one i.e 0.528 .

So,

Na : 1.06/0.528 = 2.007 ≈ 2

C : 0.528/0.528 = 1

O : 1.59/0.528 = 3.011 ≈ 3

Rounding all them to nearest integer, we will get the number of each atom in the empirical formula.

So, empirical formula is Na_2CO_3 .

Hence, this is the required solution.

5 0
2 years ago
Compute 6.28×1013+7.30×1011.
Simora [160]
6.28×1013+7.30×1011 this =13741.94
6 0
3 years ago
Tried solving this multiple ways, but keep getting the wrong answer. So, I would appreciate the help. Thank you.​
Aliun [14]

Answer:

I can give you the definition ... That might help cause I honestly don't kno the answer either ;-;

Explanation:

When used as a diacritic mark, the term dot is usually reserved for the interpunct, or to the glyphs 'combining dot above' and 'combining dot below' which may be combined with some letters of the extended Latin alphabets in use in Central European languages and Vietnamese.

Here is an example:

The dot product between a unit vector and itself is also simple to compute. In this case, the angle is zero and cosθ=1. Given that the vectors are all of length one, the dot products are i⋅i=j⋅j=k⋅k=1.

5 0
3 years ago
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