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2 years ago

#15, what is this answer ?

Mathematics

1 answer:

mezya [45]2 years ago

5 0

Answer:

43.39

Step-by-step explanation:

It's easy division/

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What is the solution to the system of equations below y=-3/4x+3 and y=12.

Alexandra [31]

The correct answer choice is D.

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3 years ago

A professor grades students on four tests, a term paper, and a final examination. Each test counts as 15% of the course grade. T

Dmitry [639]

Answer:

Marilee wants to earn an "A" in a class and needs an overall average of at least Her test grades are 88 , 92,100 , and 80 . The average of her quizzes is 90 and counts as one test grade. The final exam counts as 2.5 test grades. What scores on the final exam would result in Marilee's overall average of 92 or greater? (See Example 9

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2 years ago

Assume you have such a watch. if a minimum of 18.0% of the original tritium is needed to read the dial in dark places, for how m

laila [671]

Given that the half life of 3H is 12.3 years.

The amount of substance left of a radioactive substance with half life of $t_{ \frac{1}{2} }$ after t years is given by

$N(t)=N_0\left(\frac{1}{2} \right)^{ \frac{t}{t_{\frac{1}{2}} }$

Therefore, the number of years it will take for 18% of the original tritinum to remain is given by

$18 \% = 100 \% \left(\frac{1}{2} \right)^{ \frac{t}{12.3}} \\ \\ \Rightarrow\left(\frac{1}{2} \right)^{ \frac{t}{12.3}} =0.18 \\ \\ \Rightarrow\frac{t}{12.3}\ln\left(\frac{1}{2} \right)=\ln0.18 \\ \\ \Rightarrow\frac{t}{12.3}= \frac{\ln0.18}{\ln\left(\frac{1}{2} \right)} = \frac{-1.715}{-0.6931} =2.474\\ \\ \Rightarrow t=2.474(12.3)=30.4$

Therefore, the number of <span>years that the time could be read at night is 30.4 years.</span>

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3 years ago

What does 0.2 = in halves

GuDViN [60]

The answer is .1

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3 0

2 years ago

For concreatting a tower cement, sand, stones are in the ratio 1:2:4 For 144kg sand.. What amount of cement is required?

Verdich [7]

Answer:

72 kg

Step-by-step explanation:

For concreatting a tower cement, sand, stones are in the ratio 1:2:4 For 144kg sand.. What amount of cement is required?

We are given the ratio

cement: sand:stones

= 1:2:4

The sum of proportion =

1 + 2 + 4 = 7

We are given the kg of sand = 144kg

Step 1

We find the total kg of cement, sand and stones = x

Using the proportion of sand,

2/7 of x = 144kg

2/7 × x = 144kg

2x/7 = 144kg

Cross Multiply

2x = 7 × 144kg

x = 7 × 144kg/2

x = 504kg

Therefore the total kg of cement, sand and stone = 504kg

Step 2

The amount of cement required is calculated as:

1/7 × 504 kg = 72 kg

Therefore, 72kg of cement is required.

4 0

3 years ago