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erma4kov [3.2K]
3 years ago
10

Bob is 3 years older than twiceJohn's age. The sum of their ages is 33. How old is Bob? B = 21 +3 J J + 2] +3=33 3J+3=33 -Be-3 C

-3 3:​
Mathematics
1 answer:
Gwar [14]3 years ago
3 0

Answer:

23

Step-by-step explanation:

1. according to the condition 'Bob is 3 years older than twiceJohn's age':

B-2J=3;

2. according to the condition 'The sum of their ages is 33':

B+J=33

3. If to solve these two equations as a system, then

\left \{ {{B+J=33} \atop {B-2J=3}} \right.  \ => \left \{ {{B=23} \atop {J=10}} \right.

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