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3 years ago

If the area of a square living room is 169 square feet . What is the perimeter of the room

Mathematics

2 answers:

stich3 [128]3 years ago

8 0

The one wall would be 13 feet long.
13+13+13+13= 52 feet.

Mariana [72]3 years ago

4 0

A = s^2
169 = s^2
Take the sqrt of both sides
13 = s
P = 4s
P = 4(13)
P = 52 ft

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2 years ago

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pychu [463]

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2 years ago

Read 2 more answers

Given a rectangle with length of (2x+9)cm and width of (3x+1)cm.Two squares, each with sides x cm is removed from the rectangle.

il63 [147K]

Answer: The length is 13cm and the width is 7cm

Step-by-step explanation:

For a rectangle of length L and width W, the area is:

A = W*L

In this case we have:

L = (2*x + 9) cm

W=(3*x + 1) cm

Then the area of the rectangle is:

A = (2*x + 9)*(3*x + 1) cm^2

A = (6*x^2 + 2*x + 27*x + 9) cm^2

A = (6*x^2 + 29*x + 9) cm^2

now we remove two squares with sides of x cm

The area of each one of these squares is (x cm)*(x cm) = x^2 cm^2

Then the area of the figure will be:

area = (6*x^2 + 29*x + 9) cm^2 - (2*x^2 ) cm^2

area = (4*x^2 + 29*x + 9) cm^2

Now we know that the area of this shape is 83 cm^2, then we need to solve:

83 cm^2 = (4*x^2 + 29*x + 9) cm^2

0 = (4*x^2 + 29*x + 9) cm^2 - 83 cm^2

0 = (4*x^2 + 29*x - 74) cm^2

Then we need to solve:

0 = 4*x^2 + 29*x - 74

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$x = \frac{-29 \pm \sqrt{29^2 - 4*4*(-74)} }{2*4} = \frac{-29 \pm 45}{8}$

Then the two solutions are:

x = (-29 - 45)/8 = -9.25 (for how the length and width are defined, we can not have x as a negative number, then this solution can be discarded).

The other solution is:

x = (-29 + 45)/8 = 2

x = 2

Then the length and width of the rectangle are:

Length = (2*2 + 9)cm = 13 cm

Width = (3*2 + 1)cm = 7cm

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2 years ago

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Ann [662]

Answer:

The given point is a solution to the given system of inequalities.

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Again, we can substitute the coordinates of the given point into the system of inequalities. We know that the x-coordinate and y-coordinate of $(3,2)$ are $x=3$ and $y=2$ , respectively.

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Plugging the coordinates into the second inequality, $y\geq -x+3$ , gives us $2\geq -3+3$ , which simplifies to $2\geq 0$ . This is also a true statement, so the given point satisfies the second inequality as well. Therefore, $\bold(\bold3\bold,\bold2\bold)$ is a solution to the given system of inequalities since it satisfies all of the inequalities in the system. Hope this helps!

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