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Ganezh [65]
3 years ago
6

Find the area of a rectangle whose length is 14.6 cm and breadth is 7.4 cm​

Mathematics
1 answer:
hram777 [196]3 years ago
4 0

Answer:

108.04

Step-by-step explanation:

You find the  area by multiplying your length times width, so in this case you would be looking at the length and width of the rectangle which you already have which is 14.6 times 7.4. You multiply those 2 together to total out to an answer of 108.04

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4^6*4^-^8 = 4^6^+^-^8=4^-^2= \frac{1}{4^2} = \frac{1}{16}
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3 years ago
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If f(x) = x3 - 12x2 + 44x - 48, which of the following is not a factor of f(x)? O (x + 4) O (x - 6) O (x - 2) O (x - 4)​
denis-greek [22]

Answer:

(x + 4)

Step-by-step explanation:

x - 2 = 0, so x = 2

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8 0
2 years ago
Ben and Josh went to the roof of their 40-foot tall high school to throw their math books off the edge.
krok68 [10]

Answer:

  • Josh's book lands first
  • Ben's lands about 0.648 seconds later

Step-by-step explanation:

Using the given equation for v=60 and s=40, the height of Ben's book is ...

  h(t) = -16t² +60t +40

We want to find t when h(t) = 0, so we're looking for the solution to ....

  0 = -16t² +60t +40

Using the quadratic formula, we find the positive value of t to be ...

  t = (-60 -√(60² -4(-16)(40)))/(2(-16)) = (15 +√385)/8 ≈ 4.3277

__

Similarly, the height of Josh's book is ...

  0 = -16t² +48t +40

  t = (-48 -√(48² -4(-16)(40)))/(2(-16)) = (12 +√304)/8 ≈ 3.6794

__

The time before Josh's book lands is shorter by ...

  4.3277 -3.6794 ≈ 0.6482 . . . . . seconds

Josh's book reaches the ground first, by about 0.648 seconds.

3 0
3 years ago
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2 years ago
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What is the solution to the inequality below ?
Vlad1618 [11]
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8 0
3 years ago
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