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1 year ago

5

When the scale factor is a greater than 1 the dilation will be a reduction?

1 answer:

IceJOKER [234]1 year ago

6 0

No , When the scale factor is a greater than 1 the dilation will not be a reduction.

The process of dilation entails scaling or changing a thing. It is a transformation that uses the specified scale factor to make the objects smaller or larger.

The initial figure is referred to as the pre-image, and the new figure that results from dilatation is known as the image.

The resizing happens from a point called the center of dilation. It is the center of dilation from which the objects/figures are expanded or contracted.

Scale factor is a number by which the size of any geometrical figure can be changed with respect to its original size. We multiple the scale factor to get image.

When the scale factor is greater than 1 figure size increased.

Hence , When the scale factor is a greater than 1 the dilation will be a expansion

To know more about Dilation here

brainly.com/question/29536608

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2 years ago

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One solution to the problem below is 5 what ya the other solution a^2-25=0

Alex

-5

a^2-25=0

a^2=25

take the square root of both sides

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3 years ago

What is the result when the following code is run? double x = 1; double y = 1; int i = 0; do { y = x / 2; x = x + y; i = i + 1;

Mama L [17]

Answer:

The answer is: 3

Step-by-step explanation:

1. At the begining of the program we start by declairing the variables:

double x=1, double y=1 and int i=0.

2. The structure do...while is used to defined the loop. x<2.5 is the finalization condition of the loop. i is the counter of the loop.

y=x/2 is the first calculation

x=x+y is the second one. Here is where the values of the variable x changes.

a) for the first iteration, the values of y and x are shown below:

$\\\\x=1\\y=1\\y=1/2=0.5\\x=1+0.5=1.5\\i=1$

The variable x is minor to 2.5 so the loop will continue computing.

b) the second iteration, the values of y and x are shown below::

$y=0.5\\x=1.5\\y=\frac{1.5}{2}=0.75\\ x=1.5+0.75=2.25\\i=2$

The variable x is still minor to 2.5 so the loop will continue computing.

c) third iteration:

$y=0.75\\x=2.25\\y=\frac{2.25}{2} =1.1125\\x=2.25+1.125=3.375\\i=3$

The condition x<2.5 is not true so the loop ends.

3. System.out.print(i + " "); displays the value of the variable i wich value is 3.

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3 years ago

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andrew-mc [135]

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Step-by-step explanation:

Given

$(-5)(-5)(-5) * c * c * c$

Required

The exponent form

We have:

$(-5)(-5)(-5) * c * c * c$

Apply the following law of indices;

$x * x * x ...... = x^n$

So, the expression becomes:

$(-5)^3 * c^3$

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2 years ago

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