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Leno4ka [110]
4 years ago
12

a 1.0 kg ball is thrown into the air with an initial velocity of 30 m/s. How much kinetic energy does the ball have?

Physics
1 answer:
timama [110]4 years ago
8 0
KE=.5mv^2
KE=.5(1)(30^2)
KE=(.5)(900)
KE=450
Assuming no air resistance....

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3 years ago
A hot-air balloon is descending at a rate of 2.1 m/s when a passenger drops a camera. If the camera is 42 m above the ground whe
zysi [14]

Answer:

a) 2.7s

b) 29 m/s

Explanation:

The equation for the velocity  and position of a free fall are the following

v=v_{0}-gt -(1)

x=x_{0}+v_{0}t-gt^{2}/2 - (2)

Since the hot-air ballon is <em>descending </em>at 2.1m/s and the camera is dropped at 42 m above the ground:

v_{0}=-2.1m/s

x_{0}=42m

To calculate the time which it takes to reach the ground we use eq(2) with x=0, and look for the positive solution of t:

t = \frac{1}{84}(2.1\pm\sqrt{2.1^{2} - 4\times42\times9.81/2} )

        t = 2.71996

Rounding to two significant figures:

       t = 2.7 s

Now we calculate the velocity the camera had just before it lands using eq(1) with t=2.7s

v=-2.1-9.81*(2.71996)

      v = -28.782 m/s

Rounding to two significant figures:

      v = -29 m/s

where the minus sign indicates the downwards direction

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