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1 answer:
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Answer:
ω' = 0.815 rad/s
Explanation:
Given,
R = 1.20 m
Inertia of merry-go- round= 240 kg.m²
Rotating speed = 9 rpm =
=0.9424 rad/s
mass of the child, m = 26 kg
angular speed of the merry-go-round=?
we know
Angular momentum, L = I ω
Moment of inertia of the child
I' = m r² = 26 x 1.2² = 37.44 kgm²
Conservation of angular momentum
initial angular momentum = Final angular momentum
I ω = (I+I')ω'
240 x 0.9424 = (240+37.44) ω'
226.176= 277.44 ω'
ω' = 0.815 rad/s
new angular speed of the merry-go- round is equal to 0.815 rad/s
Answer:
E = 0.01 J
Explanation:
Given that,
The mass of the cart, m = 0.15 kg
The force constant of the spring, k = 3.58 N/m
The amplitude of the oscillations, A = 7.5 cm = 0.075 m
We need to find the total mechanical energy of the system. It can be given by the formula as follows :
Put all the values,
So, the value of total mechanical energy is equal to 0.01 J.
Answer:
1) Speed in m/s equals 22.22 m/s.
2) Speed in miles per hour equals 49.712 mph.
Explanation:
Since we know that in 1 kilometer there are 1000 meters and in 1 hour there are 3600 seconds hence we can write
Now we know that 1 mile equals 1.609 kilometer hence we conclude that 1 kilometer equals mile
Hence