From the information given, there is a 15 kg mass that needs to be accelerated to a velocity of 2.8m/s²
We use the formula: F = m × v.
Where F = force, m = mass and v = velocity.
In our case, m = 15kg and v = 2.8m/s². Therefore:
F = m × v.
F = 15 × 2.8.
F = 42.
Therefore the net force needed to accelerate the 15kg mass to 2.8m/s² is 42 kg m/s² (or 42 Newtons)
Answer:
Frictional force, F = 45.9 N
Explanation:
It is given that,
Weight of the box, W = 150 N
Acceleration,
The coefficient of static friction between the box and the wagon's surface is 0.6 and the coefficient of kinetic friction is 0.4.
It is mentioned that the box does not move relative to the wagon. The force of friction is equal to the applied force. Let a is the acceleration. So,
Frictional force is given by :
F = 45.9 N
So, the friction force on this box is closest to 45.9 N. Hence, this is the required solution.
The Noble Gases are the most unreactive b/c its outermost shell completes the energy level and is stable enough.
Elements in the each group have the same number of valence electrons.
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