Yes I worked it in my brain hahahahahah
A.
To solve, you need to get the variable by itself.
Order of operations:
Square root both sides.
(x-5)= plus/minus root 3, as 3 is not a perfect square.
Now you need to add 5 to both sides to get it to disappear on the side with the x.
x=root3 +or - 5, which can be rearranged so that 5 is the first term.
Answer:
1/2
Step-by-step explanation:
Step-by-step explanation:
1. (-3/2, 1)
2. (6,-3)
3. (8/3, 2)
4. <u>(</u><u>2</u><u>,</u><u>-4</u><u>)</u>
<u>5</u><u>.</u><u>(</u><u>-3</u><u>,</u><u>-1</u><u>)</u>
<u>6</u><u>.</u><u> </u><u>(</u><u>0</u><u>,</u><u>3</u><u>/</u><u>2</u><u>)</u>
<u>7</u><u>.</u><u> </u><u>(</u><u>4</u><u>,</u><u> </u><u>-2</u><u>)</u>
<u>8</u><u>.</u><u>(</u><u>8</u><u>,</u><u>2</u><u>)</u>
<u>9</u><u>.</u><u> </u><u>(</u><u>0</u><u>,</u><u>0</u><u>)</u>
Answer:
57 units^2
Step-by-step explanation:
First find the area of the triangle on the left
ABC
It has a base AC which is 9 units and a height of 3 units
A = 1/2 bh = 1/2 ( 9) *3 = 27/2 = 13.5
Then find the area of the triangle on the right
DE
It has a base AC which is 6 units and a height of 1 units
A = 1/2 bh = 1/2 ( 6) *1 = 3
Then find the area of the triangle on the top
It has a base AC which is 3 units and a height of 3 units
A = 1/2 bh = 1/2 ( 3) *3 = 9/2 = 4.5
Then find the area of the rectangular region
A = lw = 6*6 = 36
Add them together
13.5+3+4.5+36 =57 units^2