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Sliva [168]
3 years ago
7

I have 5 questions. Please try to answer as many as possible! It would be a big help.

Mathematics
2 answers:
Dmitry [639]3 years ago
5 0

Answer:

1. Emma's father is 40

2. 10 years ago

3. The cat is 4 years old, and the dog is 6 years old.

4. John is 3 and Annie is 5

5. Ellie is 2 years old

Genya is 58 years old

Step-by-step explanation:

I hope this helps you out!

igor_vitrenko [27]3 years ago
3 0
1.40 that’s all I rlly know
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How many complex zeros does the polynomial function have?<br> f(x)=−3x^6−2x^4+5x+6
REY [17]

one way would be to factor

I can't factor it so we will have to use Descartes' Rule of Signs which is helpful for finding how many real roots you have


it goes like this:

for a polynomial with real coefients, consider f(x)=-3x^6-2x^4+5x+6.

after arranging the terms in decending order in terms of degree, count how many times the signs of the coeffients change direction and minus 2 from that number until you get to 1 or 0. that will be the number of even roots the function can have

We have (-, -, +, +). the signs changed 1 times, so it has 1 real positive root


to get the negative roots, we evaluate f(-x) and see how many times the root changes

f(-x)=-3x^6-2x^4-5x+6

signs are (-, -, -, +). there was 1 change in sign

so the function has 1 real negative root



a total of 2 real roots


a function of degree n can have at most, n roots


our function is degree 6 so it has 6 roots

if 2 are real, then the others must be complex

6-2=4 so there are 4 complex roots


you can also show that there are only 2 real roots by using a graphing utility to see that there are only 2 real roots

7 0
3 years ago
⚠️ILL GIVE BRANLIEST!
SSSSS [86.1K]

Answer:

c

Step-by-step explanation:

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3 years ago
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