Answer:
2:3
Step-by-step explanation:
Just divide each by 6
Answer:
56 cups of water
Step-by-step explanation:
Katrina drinks 0.5 gallons of water per day
We have 7 days in a week, hence, the number of gallons of water she drinks per week is calculated as:
1 day = 0.5 gallons
7 days = x
Cross Multiply
1 day × x = 7 days × 0.5 gallons
x = 7 days × 0.5 gallons/1 day
x = 3.5 gallons
Note that 16 cups = 1 gallon
The number of cups of water she drinks per week is
1 gallon = 16 cups
3.5 gallons = x
Cross Multiply
1 gallons × x = 3.5 gallons × 16 cups
x = 3.5 gallons × 16 cups/1 gallons
x = 56 cups
Therefore, Katrina drinks 56 cups of water in a week
10. Kim gets $7 per hour and gets charged $1 for gloves
Use y to represent her pay and x to represent hours worked.
The equation is y = 7x - 1 because she gets 7 times x hours and there is a minus 1 because of the charge of gloves.
11. The table shows that each increasing hour, 8$ is added. Therefore we need to find the bonus that Kit receives just for showing up. This is when hours equals 0. If 3 hours is 27$ pay, then 2 hours is 19$ pay, 1 hour is 11$ pay and 0 hours is 3$ pay. We find that there is a 3$ bonus just for showing up.
Therefore the equation is y = 8x + 3
12. At x = 0, y = 2 so the y-intercept is 2. The slope is going down 4 and right one which means the slope is -4. The y-intercept is b and the slope is m. If we plug these values into the equation y = mx + b we get:
y = -4x + 2
13. At x = 0, y = -3 so the y-intercept is -3. The slope is going up 1 and right 4 which means the slope is 1/4. The y-intercept is b and the slope is m. If we plug these values into the equation y = mx + b we get:
y = 1/4 x - 3
Answer:
Step-by-step explanation:
q is TFTF
~q use negation, not q so is the opposite of q : FTFT
p↔~q use biconditional ,and will be True only is both statements are T or both are F
p values are TTFF ↔~q values are FTFT : FTTF
(p↔~q )∧~q use conjunction, that is True only if both statements are T
(p↔~q ) values are FTTF ∧~q values are FTFT : FTFF
(p↔~q )∧~q → p use a conditional statement, where only True False will give a F
(p↔~q )∧~q values are FTFF → p values are TTFF : TTTT