Let t be time and r be rate, then if time varies inversely with the rate, the equation is
![t= \frac{k}{r}](https://tex.z-dn.net/?f=t%3D%20%5Cfrac%7Bk%7D%7Br%7D%20)
. If it takes 5 hours to drive a fixed distance at a rate of 80, we can sub those values in to solve for the constant of variation, k.
![5= \frac{k}{80}](https://tex.z-dn.net/?f=5%3D%20%5Cfrac%7Bk%7D%7B80%7D%20)
. Solve for k by multiplying 5 and 80 to get that k = 400. Now let's find a new time t when r is a rate of 70. We will use that k value to do this:
![t= \frac{400}{70}](https://tex.z-dn.net/?f=t%3D%20%5Cfrac%7B400%7D%7B70%7D%20)
and find that it will take 20 hours to drive the distance at 70 mph when it takes 5 hours to drive the distance at 80 mph. Makes sense that it takes longer to drive a fixed distance when you are going slower.
Answer:
2g-1
Step-by-step explanation:
if you divide anything by itself the answer is 1
Your Answer Will Be 78x−11
(3*13)2*x-11
THe Symbol " * " Means Times
75<span> = 25 x 3. Therefore the </span>square root of 75<span> equals the </span>square root<span> of 25 times the </span>square root<span> of 3.</span>
Answer:
ummmmmm
Step-by-step explanation: