We have been given a quadratic function
and we need to restrict the domain such that it becomes a one to one function.
We know that vertex of this quadratic function occurs at (5,2).
Further, we know that range of this function is
.
If we restrict the domain of this function to either
or
, it will become one to one function.
Let us know find its inverse.

Upon interchanging x and y, we get:

Let us now solve this function for y.

Hence, the inverse function would be
if we restrict the domain of original function to
and the inverse function would be
if we restrict the domain to
.
Answer:
first blank: -1
second blank: -7
third blank: -13
fourth blank: - 19
Step-by-step explanation:
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Answer:
<h2>
2x + 3y = 33 </h2>
Step-by-step explanation:
As we move from (-2, 5) to (1, 3), x increases by 3 and y decreases by 2.
Hence, the slope of this line is m = rise / run = -2/3.
Start with the slope-intercept form y = mx + b.
Substitute 3 for y and 1 for x and -2/3 for m:
3 = (-2/3)(1) + b.
Remove fractions by mult. all three terms by 3:
9 = -2 + b, so b = 11, and y = (-2/3)x + 11
Again, mult. all three terms by 3:
3y = -2x + 33, or, in standard form,
<h2>
2x + 3y = 33 </h2>
Answer:
x and y = 5√2.
Step-by-step explanation:
This is a 45:45:90 triangle so length of x = length of y.
In this triangle the ratio of the sides is 1:1:√2
Finding length of x and y:
1/√2 = x/10
√2x = 10
x = 10/√2
= 10√2/2
= 5√2.