Would th eanswer be<span> two solutions are the points (0,-4) and (0,4). </span>
To negatives equal a positive. Convert both of the mixed numbers into a improper fraction. Cross simplify 5 and 5, they both turn into one’s. Multiply and you should get 7/3 or 2 1/3.
A "solution" would be a set of three numbers ... for Q, a, and c ... that
would make the equation a true statement.
If you only have one equation, then there are an infinite number of triplets
that could do it. For example, with the single equation in this question,
(Q, a, c) could be (13, 1, 2) and they could also be (16, 2, 1).
There are infinite possibilities with one equation.
In order to have a unique solution ... three definite numbers for Q, a, and c ...
you would need three equations.
Answer:
no question
Step-by-step explanation:
