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aleksley [76]
3 years ago
7

The leg of a right triangle is 2 units and the hypotenuse is 3 units. What is the length, in units, of the other leg of the tria

ngle?
Square root of 5 units
Square root of 13 units
5 units
13 units
Mathematics
2 answers:
miv72 [106K]3 years ago
8 0

Answer:

Square root of 5 units

Step-by-step explanation:

Pythagorean therom since it's a right triangle and you're trying to find the sides.

a^2 + b^2 = c^2

2^2 + b^2 = 3^2

4 + b^2 = 9

b^2 = 5

b = square root 5

Triss [41]3 years ago
3 0

Answer:

it simple e

Step-by-step explanation:

a square plus b squared

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Step-by-step explanation:

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3 years ago
A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot
ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box  is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = (x\times x)

                               =x^2

The volume of the box  is = area of the base × height

                                           =x^2h

Therefore,

x^2h=272

\Rightarrow h=\frac{272}{x^2}

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

=20x^2 cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

=10x^2 cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

=4xh\times 1.5 cents

=6xh cents

Total cost = (20x^2+10x^2+6xh)

                =30x^2+6xh

Let

C=30x^2+6xh

Putting the value of h

C=30x^2+6x\times \frac{272}{x^2}

\Rightarrow C=30x^2+\frac{1632}{x}

Differentiating with respect to x

C'=60x-\frac{1632}{x^2}

Again differentiating with respect to x

C''=60+\frac{3264}{x^3}

Now set C'=0

60x-\frac{1632}{x^2}=0

\Rightarrow 60x=\frac{1632}{x^2}

\Rightarrow x^3=\frac{1632}{60}

\Rightarrow x\approx 3

Now C''|_{x=3}=60+\frac{3264}{3^3}>0

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is =\frac{272}{3^2}

                                          =30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0
3 years ago
Which similarity statement is true?
stepan [7]

9514 1404 393

Answer:

  (a)  ΔWZY ~ ΔWXZ ~ ΔZXY

Step-by-step explanation:

In order for the similarity statement to be correct, the corresponding sides need to be listed in the same order.

A: ΔWZY lists sides in order short leg (WZ), long leg (ZY).

  ΔWXZ lists sides in order short leg (WX), long leg (XZ).

  ΔZXY lists sides in order short leg (ZX), long leg (XY).

The first similarity statement is correct.

__

You can compare this to an incorrect one, the last one, for example.

ΔYZW lists sides in order long leg (YZ), short leg (ZW).

ΔXZW lists sides in order long leg (XZ), hypotenuse (ZW). Hypotenuse and short leg are not corresponding sides, so the similarity statement is incorrect.

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