Concentration of unknown acid is 0.061 M
Given:
Concentration of NaOH = 0.125 M
Volume of NaOH = 24.68 mL
Volume of acid solution = 50.00 mL
To Find:
Concentration of the unknown acid
Solution: Concentration is the abundance of a constituent divided by the total volume of a mixture. The concentration of the solution tells you how much solute has been dissolved in the solvent
Here we will use the formula for concentration:
M1V1 = M2V2
0.125 x 24.68 = 50 x M2
M2 = 0.125 x 24.68 / 50
M2 = 0.061 M
Hence, the concentration of unknown acid is 0.061 M
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Atoms are fundamental constituents of all matter. The following statement is correct. The nucleus always has a positive charge. This is because the nucleus contains sub-atomic particles called protons. Each proton carries a single positive charge. The nucleus is also home to sub-atomic particles called neutrons that do not possess a charge.
Answer:
The equation for wave speed can be used to calculate the speed of a wave when both wavelength and wave frequency are known. Consider an ocean wave with a wavelength of 3 meters and a frequency of 1 hertz. The speed of the wave is: Speed = 3 m x 1 wave/s = 3 m/s.
SO... take your meters and hezert and do tha same
Explanation:
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Answer: Thus the new volume of the gas is 530 ml
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
![\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1V_1%7D%7BT_1%7D%3D%5Cfrac%7BP_2V_2%7D%7BT_2%7D)
where,
= initial pressure of gas = 740 torr
= final pressure of gas = 760 torr
= initial volume of gas = 500 ml
= final volume of gas = ?
= initial temperature of gas = ![25^oC=273+25=298K](https://tex.z-dn.net/?f=25%5EoC%3D273%2B25%3D298K)
= final temperature of gas = ![50^oC=273+50=323K](https://tex.z-dn.net/?f=50%5EoC%3D273%2B50%3D323K)
Now put all the given values in the above equation, we get:
![\frac{740\times 500}{298}=\frac{760\times V_2}{323}](https://tex.z-dn.net/?f=%5Cfrac%7B740%5Ctimes%20500%7D%7B298%7D%3D%5Cfrac%7B760%5Ctimes%20V_2%7D%7B323%7D)
![V_2=530ml](https://tex.z-dn.net/?f=V_2%3D530ml)
Thus the new volume of the gas is 530 ml