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kkurt [141]
3 years ago
12

Ammonium iodide dissociates reversibly to ammonia and hydrogen iodide. NH4I (s) ⇌ NH3 (g) + HI (g) At 400 ºC, Kp = 0.215. Calcul

ate the partial pressure of ammonia at equilibrium when a sufficient quantity of ammonium iodide is heated to 400 ºC. Complete the ICE box below as part of your answer.
A. 0.103 atmB. 0.215 atmC. 0.232 atmD. 0.464 atmE. 2.00 atm
Chemistry
1 answer:
ollegr [7]3 years ago
5 0

<u>Answer:</u> The partial pressure of ammonia is 0.464 atm

<u>Explanation:</u>

For the given chemical equation:

                  NH_4I(s)\rightleftharpoons NH_3(g)+HI(g)

Initial:               1

At eqllm:        1-x                 x         x

The expression for K_p for the following equation is:

K_p=p_{NH_3}\times p_{HI}

The partial pressures of solids and liquids are taken as 1 in the equilibrium expression.

We are given:

K_p=0.215

Putting values in above equation, we get:

0.215=x\times x\\\\x=0.464atm

Hence, the partial pressure of ammonia is 0.464 atm

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During the titration of a diluted vinegar sample with a sodium hydroxide solution, the volume of sodium hydroxide used was less
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Answer:

B and D could be true

Explanation:

A volume of sodium hydroxide less than expected could occurs for two reasons:

The real concentration of sodium hydroxide was higher than expected or the amount of vinegar added was less than expected:

A. The sodium hydroxide solution had been allowed to stand exposed to the air for a long time prior to the titration.  FALSE. A long expose  to the air decreases concentration of the NaOH.

B. The volumetric flask used to prepare the diluted vinegar solution was rinsed with water prior to use.  TRUE. You add a less amount of vinegar doing you require less amount of NaOH than expected.

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0.023 M solution of perchloric acid
kogti [31]
The original question is to find the pH and the pOH of 0.023 M of perchloric acid.

Answer:
pH = 1.638
pOH = 12.362

Explanation:
1- getting the pH:
pH can be calculated using the following rule:
pH = -log[H+]
Since the given solution is an acid, this means that [H+] is the same as the concentration of the solution.
This means that:
[H+] = 0.023
Substitute in the above equation to get the pH as follows:
pH = -log[0.023]
pH = 1.638

2- getting the pOH:
We know that:
pH + pOH = 14
We have calculated that pH = 1.638.
Substitute in the above equation to get the pOH as follows:
pOH + 1.638 = 14
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pOH = 12.362

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