The answer is going to be mercury
Answer:
30kg m/s.
Explanation:
30 kg m/s
Explanation
Momentum = Mass × Velocity = 10 kg × 3 m/s = 30 kg m/s
Its momentum is 30 kg m/s.
Explanation:
Momentum is defined by the following equation:
p=mv
where m is the mass of the object in kilograms, v is the velocity of the object in meters per second
p=10 kg⋅3 m/s
=30 kg m/s
Also nice photo.
111.1 mL of water
Explanation:
Weight per volume concentration (w/v %) is defined as
weight per volume concentration = (mass of solute (g) / volume of solution (mL)) × 100
volume of solution = (mass of solute × 100) / weight per volume concentration
volume of solution = (1 × 100) / 0.9 = 111.1 mL
volume of water = volume of solution = 111.1 mL
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weight per volume concentration
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The answer has to depend on the mass of the copper that you're trying to melt.
But there is a formula which you can calculate the energy required if you have the information of the mass. This formula requires the value called specific latent heat of fusion, which is the energy required to melt or freeze a specific mass of copper without changing its temperature but change its state.

E is the total energy required, m is the mass, and lv is the specific latent heat of fusion of copper.
Usually, in questions, lv is given. But we can also look it up online which is around 205kJ kg^-1
this means, to melt or freeze a copper, we need to work the mass multiplied by 205kJ in order to calculate its total energy needed or released.
<span>BaCl2+Na2SO4---->BaSO4+2NaCl
There is 1.0g of BaCl2 and 1.0g of Na2SO4, which is the limiting reagent?
"First convert grams into moles"
1.0g BaCl2 * (1 mol BaCl2 / 208.2g BaCl2) = 4.8 x 10^-3 mol BaCl2
1.0g Na2SO4 * (1 mol Na2SO4 / 142.04g Na2SO4) = 7.0 x 10^-3 mol Na2SO4
(7.0 x 10^-3 mol Na2SO4 / 4.8 x 10^-3 mol BaCl2 ) = 1.5 mol Na2SO4 / mol BaCl2
"From this ratio compare it to the equation, BaCl2+Na2SO4---->BaSO4+2NaCl"
The equation shows that for every mol of BaCl2 requires 1 mol of Na2SO4. But we found that there is 1.5 mol of Na2SO4 per mol of BaCl2. Therefore, BaCl2 is the limiting reagent.</span>