Answer:
103.00
Explanation:
1 mole of Glucose
6 C = 6 * 12 = 72 grams
12H = 12 * 1 = 12 grams
6O = 6 * 16 =96 grams
Total = 180 grams
0.572 moles of Glucose
1 mol of glucose = 180 grams
0.572 mols of glucose = x
x = 0.572 * 180
x = 103.00 grams
There are 6 atoms of oxygen on the reactant side of the following equation: 2Fe2O3 + 3C → 4Fe + 3CO2. Details about atoms can be found below.
<h3>How to find number of atoms?</h3>
The number of atoms of an element in a balanced equation is the amount of that element involved in the reaction.
According to this question, Iron oxide reacts with carbon to produce iron and carbon dioxide as follows:
2Fe2O3 + 3C → 4Fe + 3CO2
In this reaction, 2 × 3 atoms = 6 atoms of oxygen are present on the reactant side of the equation.
Learn more about number of atoms at: brainly.com/question/8834373
#SPJ1
Answer:
0.21mol Ar (g)
Explanation:
To convert from litres to moles at STP we must divide the amount of litres by 22.4.
4.7 / 22.4 = 0.21mol Ar (g)
Answer is: <span>the empirical formula of the hydrocarbon is CH</span>₂.<span>
Chemical reaction: C</span>ₓHₐ + O₂ → xC + a/2H₂O.<span>
m(CO</span>₂) = 33.01 g.
n(CO₂) = m(CO₂) ÷ M(CO₂).
n(CO₂) = 33.01 g ÷ 44.01 g/mol.
n(CO₂) = n(C) = 0.75 mol.
m(H₂O) = 13.52 g.
n(H₂O) = 13.52 g ÷ 18 g/mol.
n(H₂O) = 0.75 mol.
n(H) = 2 · n(H₂O) = 1.5 mol.
n(C) : n(H) = 0.75 mol : 1.5 mol /0.75 mol.
n(C) : n(H) = 1 : 2.
The strategy for balancing the equations is by looking at the number of atoms on each side of the equation and adding coefficients to the molecules.
<h3>What is a balanced equation?</h3>
A balanced equation is an equation for a chemical reaction where the number of atoms for each element in the reaction and the total charge is the same for the reactants and the products,
A strategy that will help balance equations more quickly is balancing by inspection. Here, you look at how many atoms you have on each side of the equation and add coefficients to the molecules to balance out the number of atoms.
Learn more about atoms on:
brainly.com/question/6258301
#SPJ1
