Answer:
Hi! I believe this is your answer:
52 kilograms
Hope this helps, sorry if it's wrong!
Explanation:
Answer:
A base that forms K⁺ and OH⁻ ions.
Explanation:
The KOH is an Arrhenius base.
A is <em>wrong</em>. A base does not form H⁺ ions.
B is <em>wrong</em>. A metal hydroxide forms K⁺ ions, not KO⁻ ions.
D is <em>wrong</em>. The metal forms K⁺ ions, KO⁻ ions.
Get to know first how many moles in the gas:n = pV/RT= (1.013*10^5*750/760) Pa *1.49*10^-3 m^3/(8.314 J/(molK)*298) n = 0.0601 moles.
The combustion energies are 889 kJ/mol (methane) and 2 220 kJ (propane) x = moles methane, y = moles propane
x*889 + y*2220 = 778 x + y = 0.0601----------- x = 0.267784 moles = 0.267784*100/0.0601 = 44.6 % y = 0.243216 moles = 0.243216*100/0.0601 = 55.4 %
Answer:
The answer to your question is -2855 J
Explanation:
Reaction
2C₂H₆ + 7O₂ ⇒ 4CO₂ + 6H₂O
Formula
Heat of reaction = ΔHrxn = ΣΔHrxn products - ΣΔHrxn reactants
Substitution
ΔHrxn = { 4(-393.5) + 6(-241.8)} - {2(-84.7) + 7(0)}
ΔHrxn = {-1574 -1450.8} - {-169.4}
ΔHrxn = -3024.8 + 169.4
ΔHrxn = -2855.4 J
