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Roman55 [17]
2 years ago
10

Please Help Factor the polynomial: x^3 + 3x - 2x - 6

Mathematics
1 answer:
madreJ [45]2 years ago
6 0

Answer:

(x^2-2)(x+3)

Step-by-step explanation:

x^3 + 3x^2 - 2x - 6

x^2(x+3)-2(x+3)

(x^2-2)(x+3)

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Gillian earns $7.50 an hour babysitting on the weekends.Last week she babysat for 2.2 hours on Saturday and 3.5 hours on Sunday.
Musya8 [376]

Total hours= 2.2+3.5=5.7

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8 0
4 years ago
The points with coordinates (x, -1), (2,2), and (4,3) lie on the same line. What is the value of x?
borishaifa [10]

Find the slope of the line passing throught the points (2, 2) and (4, 3).

The formula of a slope:

m=\dfrac{y_2-y_1}{x_2-x_1}

Substitute:

m=\dfrac{3-2}{4-2}=\dfrac{1}{2}

If the point (x, -1) lie on the same line, then the slope of line passing through the points (2, 2) and (x, -1) the same:

Substitute:

m=\dfrac{-1-2}{x-2}=\dfrac{-3}{x-2}

We have the equation:

\dfrac{-3}{x-2}=\dfrac{1}{2}        <em>cross multiply</em>

(1)(x-2)=(-3)(2)

x-2=-6           <em>add 2 to both sides</em>

x=-4

<h3>Answer: x = -4.</h3>
7 0
3 years ago
Find the vertical, horizontal, and slant asymptotes, if any for y=x^3/ (x-2)^4
VashaNatasha [74]
This has both a horizontal and a vertical asymptote.  There are no slant (oblique) asymptotes cuz the degree of the numerator is not higher than that of the denominator.  If the degree of the numerator is less than the degree of the denominator, which is our case here, then the horizontal asymptote is 0.  But we also have a vertical asymptote, which occurs where the denominator = 0.  We all know that we break every rule known to mankind if we try to divide by 0, so there also a vertical asymptote at x = 2.
7 0
3 years ago
10=12-x what would match this equation
Eddi Din [679]

Answer:

x=2

Step-by-step explanation:

12-10=2

6 0
4 years ago
Read 2 more answers
1 5/6 divided by 11/12
deff fn [24]
First convert the mixed number to a fraction: 1 5/6 = 11/6.
\frac{\frac{11}{6}}{\frac{11}{12}}=\frac{11}{6}\times\frac{12}{11}=2
8 0
3 years ago
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