AngleDFG and angleJKL are complementary angles. M angleDFG =x+5, and m angleJKL=x-9. Find the measure of each angle

1 answer:

4 0

$Measures\ of\ complementary\ angles\ make\ sum\ equal\ to\ 90^{\circ}.\\\\
\angle DFG+\angle JKL=90^{\circ}\\\\
x+5+x-9=90\\\\
2x=90-5+9\\\\
2x=94\ \ \ |:2\\\\x=47^{\circ}\\\\
\angle DFG=x+5=47+5=52^{\circ}\\ \angle JKL=x-9=47-9=38^{\circ}$

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Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calcul

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The expression $5 = \sqrt{(x-6^2)+(y - 5)^2}$ can be used to find the coordinate of Point B. Option C is correct.

Given that,
Segment AB has point A located at (6, 5). If the distance from A to B is 5 units, which of the following could be used to calculate the coordinates for point B is to be determined.

<h3>What is the equation?</h3>

The equation is the relationship between variables and represented as y = ax +c is an example of a polynomial equation.

Let the coordinates of B be (x, y)
Now the distance between A (6, 5) and B (x, y) is c = 5 units
So, by the distance formula, the distance between two points is given as,

$C = \sqrt{(x_1-x_2)^2 +(y_1-y_2)^2}$