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emmasim [6.3K]
3 years ago
13

Rick made a paper football that was 1 1/6 inches long Carly made one that was 5/6 inches long how many longer was Rick's paper f

ootball than Carly's
Mathematics
2 answers:
n200080 [17]3 years ago
7 0
2/6 also know as 1/3 this is what i got i hope it helps

Alex17521 [72]3 years ago
5 0
6 I believe if this is wrong sorry
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Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby. Thi
Dovator [93]

Complete question:

Assume that different groups of couples use a particular method of gender selection and each couple gives birth to one baby this mention is designed to increase the likelihood that each baby will be a girl, but assume that the method has no effect so the probability of a girl is 0.5. Assume that the group consists of 36 couples.

A) Find the mean and standard deviation for the number of girls in groups of 36 births.

B) Use the range rule of thumb to find the values separating results that are significantly low and significantly high.

C) Is the result of 33 girls significantly high? A result of 33 girls would suggest the method is effective or is not effective?

Answer:

a) mean = 18

Standard deviation =3

b) low range = 12

High range = 24

c) The result of 33 girls is significantly high. Yes, the method is effective.

Step-by-step explanation:

Given:

p = 0.5

n = 36

a) The mean is the product of n and p

Mean u = np

u = 36 * 0.5 = 18

The standard deviation is the square root of the product of n and p&q.

S.d ó = \sqrt{npq}

= \sqrt{np(1-p)}

= \sqrt{36(0.5)(1-0.5)} = \sqrt{9} = 3

b) To find the range rule of thumb:

• For low range

Low range = u - 2ó

= 18 - (2 * 3)

= 12

• High range

= u + 2ó

= 18 + (2*3)

= 24

c) The result is significantly high, because 33 is greater than 24 girls.

A result of 33 girls would prove the method as effective.

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3 years ago
Given two terms in artimetic sequence find the common difference, the 52 term, and the explicit formula. A15=139 and A30=259
quester [9]

139, 149, 159, 169, 179, 189, 199, 209, 219, 229, 239, 249, 259.


The common difference is 13.


Let n = 52


Let d = common difference


a_52 = 139 + (52 - 1)(13)


a_52 = 139 + (51)(13)


a_52 = 139 + 663


a_52 = 802




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3 years ago
The Buffalo Bills football team wanted to buy new footballs. what did the team have to pay per football? Be sure to explain all
iogann1982 [59]

Answer: I don't see the amount per football

Step-by-step explanation:

6 0
3 years ago
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