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arsen [322]
2 years ago
5

What is 5+x^2=2x^2+13?

Mathematics
1 answer:
pshichka [43]2 years ago
4 0
Take the root of both sides, and solve.

x = 2i sqrt 2, -2i sqrt 2.
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Factor the trinomial x^2 - 7x + 10
Valentin [98]

Answer:

(x-5) (x-2)

Step-by-step explanation:

x^2 (-2x-5x) +10

basically you will write the equation down and then to double check multiply the x and then the -5 into (x-2). this can be repetitive if you get it wrong so try to do numbers that make sense.

7 0
3 years ago
Which of the following describes how to calculate the total investment in a load fund?
suter [353]
To calculate the total investment in a load fund, B.) MULTIPLY THE NUMBER OF SHARES BY THE OFFER PRICE.

Load fund is a mutual fund. The term "load" is used to refer to a fund with commission. 

The commission is the difference of the net asset value and the offer price of the fund.


7 0
3 years ago
Read 2 more answers
What is the sum of (x - 8) - (2x + 2)
Dahasolnce [82]

Answer:

the answer is 4

7 0
2 years ago
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1. y = x2 + 8x + 15<br> Find the zeros of the function by rewriting the function in intercept form
lubasha [3.4K]

The zeros of given function y=x^{2}+8 x+15 is – 5 and – 3

<u>Solution:</u>

\text { Given, equation is } y=x^{2}+8 x+15

We have to find the zeros of the function by rewriting the function in intercept form.

By using intercept form, we can put value of y as  to obtain zeros of function

We know that, intercept form of above equation is x^{2}+8 x+15=0

\text { Splitting } 8 x \text { as }(5+3) x \text { and } 15 \text { as } 5 \times 3

\begin{array}{l}{\rightarrow x^{2}+(5+3) x+5 \times 3=0} \\\\ {\rightarrow x^{2}+5 x+3 x+5 \times 3=0}\end{array}

Taking “x” as common from first two terms and “3” as common from last two terms

x (x + 5) + 3(x + 5) = 0

(x + 5)(x + 3) = 0

Equating to 0 we get,

x + 5 = 0 or x + 3 = 0

x = - 5 or – 3

Hence, the zeroes of the given function are – 5 and – 3

5 0
3 years ago
What is the unit rate of five and 15?
-BARSIC- [3]
For miles... 0.333333 Miles per Mile
6 0
2 years ago
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