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NISA [10]
3 years ago
11

What is the domain of the function y = ^3 sqrt x ??

Mathematics
2 answers:
anygoal [31]3 years ago
8 0

Answer:

Option 1 negative (-) infinity < X < infinity

Step-by-step explanation:

OlgaM077 [116]3 years ago
3 0

Answer:

-∞ < x < ∞

Explanation:

x³ is the inverse of ∛x and x³ has range of all real numbers and is one to one function, so its inverse will have domain of all real numbers.

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Consider functions f and g.1 + 12f(1) = 12 + 4. – 12for * # 2 and 7 -64.2 – 16. + 1641 +48for a # -12 Which expression is equal
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Given the following functions below,

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Factorising the denominators of both functions,

Factorising the denominator of f(x),

\begin{gathered} f(x)=\frac{x+12}{x^2+4x-12}=\frac{x+12}{x^2+6x-2x-12}=\frac{x+12}{x(x+6)-2(x+6)}=\frac{x+12}{(x-2)(x+6)} \\ f(x)=\frac{x+12}{(x-2)(x+6)} \end{gathered}

Factorising the denominator of g(x),

\begin{gathered} g(x)=\frac{4x^2-16x+16}{4x+48}=\frac{4(x^2-4x+4)}{4(x+12)} \\ \text{Cancel out 4 from both numerator and denominator} \\ g(x)=\frac{x^2-4x+4}{x+12}=\frac{x^2-2x-2x+4}{x+12}=\frac{x(x-2)-2(x-2)}{x+12}=\frac{(x-2)^2}{x+12} \\ g(x)=\frac{(x-2)^2}{x+12} \end{gathered}

Multiplying both functions,

undefined

4 0
1 year ago
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20/7 = <span>2.85714285714

If you are trying to round to the nearest tenth, the next decimal place (hundredths) is a 5, so you must round 2.8 up one more digit.

Your final answer is that</span> 20/7 = 2.9 when rounded to the nearest tenth.
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