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tia_tia [17]
3 years ago
7

Can someone please help, ty!!

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
3 0
The y intercept is 32 :)
agasfer [191]3 years ago
3 0

Answer:

32

Step-by-step explanation:

slope:

m = (y₂ - y₁) / (x₂ - x₁)

   = (32 - 14) / 0 - (-6)

   = 18 / 6

   = 3

y-intercept, use any point to determine b, let's use (2, 38) :

y = mx + b

38 = 3(2) + b

38 = 6 + b

b = 32

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Group of answer choices<br><br> 33<br><br> 50<br><br> 52<br><br> 55
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Answer:

33

Step-by-step explanation:

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2 years ago
Steven brought a shirt and a pair of shoes for $95.50. If the shirt costs $12.30 more than the shoes, what was the price of the
storchak [24]
53.95 dollars (yes that is correct)
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3 years ago
4n - 2n = 4<br> Can someone help me solve this?
Semmy [17]

Answer:

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Step-by-step explanation:

i know this is right

6 0
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Read 2 more answers
Quadrilateral ABCD has vertices A(-3, 4), B(1, 3), C(3, 6), and D(1, 6). Match each set of vertices of quadrilateral EFGH with t
Maru [420]

Answer:

See explanation

Step-by-step explanation:

First plot points A, B, C and D on the coordinate plane and connect them to get quadrilateral ABCD. Then plot the vertices E, F, G, H of the quadrilateral EFGH in each case.

For each of these cases there are attached diagrams

1 case - reflection acraoss the x-axis

2 case - translation 5 units down

3 case - reflection across the y-axis

4 case - translation 7 units right

3 0
3 years ago
The function h(x) is given below:
g100num [7]

Step-by-step explanation:

The domain and range of a function and its inverse are inverted i.e. The domain of the function will become range of its inverse and the range of the function will become the domain of its inverse.

When representing the function in ordered pairs, the first values in the pair represents the domain and second values represent the range of the function.

h(x) = {3,5),(5,-7)(6,-9)(10,-12)(12,16)}

Domain of h(x) is: {3, 5, 6, 10, 12}

Range of h(x) is: (5, -7, -9, -12, 16}

So,

Domain of h^{-1}(x) = Range of h(x) = (5, -7, -9, -12, 16}

Range of h^{-1}(x) = Domain of h(x) = {3, 5, 6, 10, 12}

Therefore, h^{-1}(x) will be represented as:

{(5,3), (-7,5), (-9, 6), (-12, 10), (16,12)}

It seems like you have made some error while writing the original function because of which we are not getting an exact match in the answer. However by looking at the answers, option B is the nearest most and seems the correct answer.

6 0
3 years ago
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