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Andre45 [30]
3 years ago
7

Jalil and Victoria are each asked to solve the equation ax – c = bx + d for x. Jalil says it is not possible to isolate x becaus

e each x has a different unknown coefficient. Victoria believes there is a solution, and shows Jalil her work: ax – c = bx + d ax – bx = d + c x (a – b) = d + c x = x equals StartFraction d plus c Over a minus b EndFraction. How can Victoria justify Step 3 of her work? Rewrite the expression on the left using the distributive property. Multiply both sides by x. Rewrite the expression on the left using subtraction. Divide both sides by x.
Mathematics
2 answers:
olchik [2.2K]3 years ago
7 0

Answer:

A on Edg 2020

Step-by-step explanation:

LUCKY_DIMON [66]3 years ago
4 0

Answer:

Step-by-step explanation:

Give the expression ax – c = bx + d, we are isolate x i.e we are to make x the subject of the formula.

ax – c = bx + d

Step 1: subtract bx from both sides

ax – c = bx + d

ax-bx = d+c

Step 2: Factor out x in the left hand side of the resulting expression

x(a-b) = d+c

Step 3: Divide both sides by the coefficient of i.e (a-b)

\frac{x(a-b)}{a-b} = \frac{d+c}{a-b}

x = \frac{d+c}{a-b}

Hence Victoria can justify the step 3 of her work by dividing both sides of the expression in 2 by a-b

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In the past, 35% of the students at ABC University were in the Business College, 35% of the students were in the Liberal Arts Co
sukhopar [10]

Answer:

a. proportions have not changed significantly

Step-by-step explanation:

Given

Business College= 35 %

Arts College= 35 %

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Calculated

Business College = 90/300= 9/30= 0.3 or 30%

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First we find the mean and variance of the three colleges using the formulas :

Mean = np

Standard Deviation= s= \sqrt{npq\\}

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Mean = np =300*0.3= 90

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Arts College

Mean = np =300*0.4= 120

Standard Deviation= s= \sqrt{npq\\}=\sqrt{0.4*0.6*300}=  8.49

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Standard Deviation= s= \sqrt{npq\\}=\sqrt{0.3*0.7*300}= 7.94

Now calculating the previous means with the same number of students

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Now formulate the null and alternative hypothesis

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90≤ Mean≥105

Arts College

105 ≤ Mean≥ 120

Education College

U0 : mean= 90     U1: mean ≠ 90

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