What is one one hundredth of 305?

Greatest common factor of three univariate monomials. Find the greatest common factor of these three expressions.

Mice21 [21]

Answer:

$9w^{2}$

Step-by-step explanation:

An easy way to find the GCF of different numbers is to list out all of their factors. In this case, the coefficients share multiple factors, but the largest is 9.

Additionally, when dividing variables with different powers you subtract the exponents. So, if you were to divide $\frac{w^3}{w^2}$ the final answer would be $w$ because 3-2 is 1. So, to find the GCF of like variables find the biggest number that can be subtracted from all of them. In this case, that is 2; therefore, the GCF of the variables is $w^2$ . Put the 2 parts together for the final answer $9w^{2}$ .

7 0

3 years ago

Here are summary statistics for randomly selected weights of newborn girls: nequals=174174, x overbarxequals=30.930.9 hg, seq

MaRussiya [10]

Answer:

The 95% confidence interval would be given by (29.780;32.020)

Step-by-step explanation:

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=30.9$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

s=7.5 represent the sample standard deviation

n=174 represent the sample size

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=174-1=173$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a tabel to find the critical value. The excel command would be: "=-T.INV(0.025,173)".And we see that $t_{\alpha/2}=1.97$ , this value is similar to the obtained with the normal standard distribution since the sample size is large to approximate the t distribution with the normal distribution.

Now we have everything in order to replace into formula (1):

$30.9-1.97\frac{7.5}{\sqrt{174}}=29.780$

$30.9+1.97\frac{7.5}{\sqrt{174}}=32.020$

So on this case the 95% confidence interval would be given by (29.780;32.020)

The value 29.6 is not contained on the interval calculated.

5 0

3 years ago

Find the volume if the cylinder. round to the nearest tenth if nessesary.

Flura [38]

The correct Answer is : B. 843.4m^3.

5 0

3 years ago

Whole numbers are _____ integers.

MrRa [10]

Whole numbers are always integers. If the integer is negative, that makes it a negative integer. If it's positive, it's a positive integer.

6 0

3 years ago

Brad and four friends go to the movies each person buy a movie ticket for $7 a snack for $5 and a drink for $2 write an expressi

Vladimir [108]

((4+1)7)+((4+1)5)+((4+1)2)
(5*7)+(5*5)+(5*2)
5(7+5+2)
5(14)

*those are all versions of the expression, from rawest form to fully simplified

Total Cost: 70 dollars

5 0

3 years ago