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Katarina [22]
3 years ago
8

Knowing that 6 < x < 7 and 10 < y < 12, find the possible values of

Mathematics
1 answer:
madam [21]3 years ago
6 0

Answer:

x+y:

16<x+y<19

y-x:

3<y-x<6

xy:

60<xy<84

y/x:

10/7<y/x<2

Step-by-step explanation:

For x+y, it'll be

  6<x<7

+

  10<y<12

=16<x+y<19

____

y-x:

  10<y<12

--

  6<x<7

because of the negative sign the x inequality is reversed so it is -7<x<-6

and then you do the math and get 3<y-x<5

________

xy:

   10<y<12

x

   6<x<7

you multiply and get 60<xy<84

________

y/x:

  10<y<12

divided by

  6<x<7

now what you do is you have to switch around the signs for the x inequality and everything becomes its reciprocal. So the x inequality becomes 1/7<1/x<1/6 and then you multiply and get 10/7<y/x<12/6

Please give me a brainliest award. This took so long. I hope this helped.

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