A cube has a volume of 1/8. If the cube holds 24 of these sugar cubes, what is the total volume of the box?

Mathematics

2 answers:

svetlana [45]3 years ago

8 0

$\frac{1}{8} \div 24 = 3$

Vilka [71]3 years ago

7 0

Answer:

the answer is 3 in.3

Step-by-step explanation:

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Identify all the numbered angles that are congruent to the given angle.

wariber [46]

Answer:

Angles 1, 4, and 7

Step-by-step explanation:

This is because angle 1 and the angle with 27 degrees are opposite angles and angle 4 because it is a corresponding angle, and because of angle 4 angle 7 because angles 4 and 7 are opposite diagonal angles

5 0

3 years ago

Solve the equation using the zero-product property. (2x − 8)(7x + 5) = 0 x = –2 or x = 7 x = 4 or x = x = 4 or x = x = –4 or x =

aliya0001 [1]

$(2x-8)(7x+5)=0\iff2x-8=0\ \vee\ 7x+5=0\\\\2x-8=0\qquad\text{add 8 to both sides}\\2x=8\qquad\text{divide both sides by 2}\\\boxed{x=4}\\\\7x+5=0\qquad\text{subtract 5 from both sides}\\7x=-5\qquad\text{divide both sides by 7}\\\boxed{x=-\dfrac{5}{7}}$

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3 years ago

The lengths of the sides of a triangle are 3, 3, and the square root 3. Can the triangle be a right triangle?

Readme [11.4K]

First find the decimal equivalent of square root 3: SQRT(3) = 1.732 ( roughly)

If the base and height were each 3, then the hypotenuse would need to be:

3^2 + 3^2 = C^2
9 + 9 = C^2
18 = C^2
C = SQRT(18) = 4.24

This is larger than sqrt(3), so this cannot be a right triangle.

If one leg was 3 and the other leg was sqrt(3) then the hypotenuse would be:
3^2 + 1.73^2 = C^2
9 + 3 = C^2
12 = C^2
C = SQRT(12) = 3.46

This is larger than 3, this cannot be a right triangle.

The answer is b) no.

8 0

3 years ago

Read 2 more answers

Derek is playing a prank on Grace and hid her pencil inside a tissue box that has a width of 4 inches, a length of 8 inches, and

ohaa [14]

Answer:

9.8 Inch

Step-by-step explanation:

The distance from the upper left corner to the bottom right corner of the box is the longest diagonal of the box.

For a rectangular prism:

Length of the Longest diagonal $=\sqrt{ l^2+h^2+w^2}$