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3 years ago

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A quarter-wave monopole radio antenna (also called a Marconi antenna) consists of a long conductor of one quarter the length of

the transmitted wavelength. The lower end of the antenna is connected to a conducting ground plane (often simply the Earth) which reflects the transmitted signal, creating an effective antenna length of a half wavelength. (a) What must be the height of the antenna (in m) for a radio station broadcasting at 514 kHz

1 answer:

alexandr402 [8]3 years ago

3 0

Answer:

145.91 m

Explanation:

Data provided in the the question:

Wavelength of radio wave, $\lambda = \frac c f$

Here, c is speed of radio wave in air = 3 × 10⁸ m/s

f is the frequency = 514 kHz = 514 × 10³ Hz

Thus,

Wavelength = (3 × 10⁸) ÷ (514 × 10³) m

or

Wavelength = 583.65 m

Thus,

The height of the antenna will be

= $\frac \lambda 4$ = 583.65 ÷ 4 m

= 145.91 m

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<u>Circular Motion </u>

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$w_2=38.426-0.00576 \ 3240=19.76 \ rad/s$

They both result in the same, as expected

$\boxed{w=19.76 \ rad/s}$

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