52800000000000000000000000000000000000000000
I think you almost got it.
At the top, the velocity only has horizontal component, so v=12 m/s is v_x, which is v*cos(theta), because v_x is constant, so the same when it was launched or now.
With the value of the initial speed (28 m/s, which is the total speed), you can set
v_x = v * cos( theta ) ---> 12 = 28*cos(theta) --> cos(theta)=12/28=3/7
or theta = 64.62 deg, it is D. Think about it. I hope you see it.
This is 6th grade earth science right?
Answer:
The current in the wire is 31.96 A.
Explanation:
The current in the wire can be calculated as follows:

<u>Where</u>:
q: is the electric charge transferred through the surface
t: is the time
The charge, q, is:

<u>Where</u>:
n: is the number of electrons = 7.93x10²⁰
e: is the electron's charge = 1.6x10⁻¹⁹ C

Hence, the current in the wire is:

Therefore, the current in the wire is 31.96 A.
I hope it helps you!
Answer here
The displacement of the cars is somewhere near 0 miles since they virtually finish where they started. Yet the successful cars have covered a distance of 500 miles