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nirvana33 [79]
3 years ago
14

If a wheel falls from an airplane that is flying horizontally at an altitude of 500 m, how long will it take for the wheel to st

rike the ground?
10 s
50 s
80 s
100 s
Physics
1 answer:
IrinaK [193]3 years ago
5 0
Even though the plane is moving horizontally, the only thing that matters for figuring out how long it’ll take the whee to fall are vertical forces.

In this case the only vertical force is gravity, which has an acceleration of 9.8m/s^2. We are also given height (distance) and starting velocity (0 m/s). We need to solve for time. The equation that incorporates these variables is:

d = vt + ½ at^2
500 = 0t + ½ (9.8)t^2
500 = 4.9t^2
t^2 = 102
t = 10.1 seconds
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Fk = μK N

N = m a

N = 4 × a

N = 4a

Fk = μK N

17 = 5 × 4a

17 = 20 a

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A flywheel with a radius of 0.300 m starts from rest and accelerates with a constant angular acceleration of 0.600 rad/s2. Compu
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Answer:

0.42 m/s²

Explanation:

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w₀ = initial angular speed = 0 rad/s

w = final angular speed = ?

θ = angular displacement = 60 deg = 1.05 rad

α = angular acceleration = 0.6 rad/s²

Using the equation

w² = w₀² + 2 α θ

w² = 0² + 2 (0.6) (1.05)

w = 1.12 rad/s

Tangential acceleration is given as

a_{t} = r α = (0.300) (0.6) = 0.18 m/s²

Radial acceleration is given as

a_{r} = r w² = (0.300) (1.12)² = 0.38 m/s²

Magnitude of resultant acceleration is given as

a = \sqrt{a_{t}^{2} + a_{r}^{2}}

a = \sqrt{0.18^{2} + 0.38^{2}}

a = 0.42 m/s²

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4 years ago
A 6.7 kg block is released from rest on a frictionless inclined plane making an angle of 25.7° with the horizontal. Calculate th
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Answer:

So time taken by block to travel 0.5 m from rest will be 0.4853 sec

Explanation:

We have given mass of the block m = 6.7 kg

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Acceleration of the block a=gsin\Theta =9.8\times sin25.7^{\circ}=4.243m/sec^2

From second equation of motion we know that S=ut+\frac{1}{2}at^2

So 0.5=0\times t+\frac{1}{2}\times 4.243\times t^2

t^2=0.2356

t = 0.4853 sec

So time taken by block to travel 0.5 m from rest will be 0.4853 sec

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