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rodikova [14]
4 years ago
12

Find the indicated term of the given geometric sequence, a1=18, r=2.1, n=12

Mathematics
1 answer:
Bezzdna [24]4 years ago
6 0
The general term of a geometric sequence is
  an = a1·r^(n-1)
Fill in the given numbers and do the arithmetic.
  a12 = 18·2.1^(12-1)
  a12 = 63,049.95009759978

_____
When a number with one decimal place is raised to the 11th power, the result is a number with 11 decimal places. It would seem you are expected to round this to some lesser number of decimal places. The number shown is exact. You can round it according to your needs.
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A sandbox is twice as long as it is wide. It’s area is 72in square. What is the perimeter of the sandbox?
melamori03 [73]

Answer:

let the width be 'x'

length = 2x

Area = 72 in square

(2x)(x)= 72

2x^2=72

x^2=36

x=6

perimeter = 2(l+b)

=2(2x+x)

=2(3x)

=2(3*6)

=2(18)

=36 inches

therefore the answer is option D

Hope it helps.............

6 0
3 years ago
PLEASEE HELP!!
Alex777 [14]

Answer:

<h2>A)t=6.7</h2>

Step-by-step explanation:

<h3>to understand this</h3><h3>you need to know about:</h3>
  • quadratic equation
  • quadratic equation word problems
  • solving quadratic
<h3>given:</h3>

h(t) = -4t² + 12t + 100

<h3>to solve:</h3>

t

<h3>tips and formulas:</h3>
  • <u>the</u><u> </u><u>Ball</u><u> </u><u>will</u><u> </u><u>hit </u><u>the</u><u> ground</u><u> </u><u>when</u><u> </u><u>the</u><u> height</u><u> is</u><u> </u><u>0</u>
  • <u>solving</u><u> </u><u>quadratics </u><u>using</u><u> </u><u>quadratic</u><u> formula</u>
  • <u>PEMDAS</u>
<h3>let's solve: </h3>

step - 1 :  \: define

- 4 {t}^{2}  + 12t + 100 = 0

step - 2 :  \\ divide \: both \: sides \: by \:  - 4

{t}^{2}  - 3t - 25 = 0

step - 3 :  \\ solve \: the \: quadratic

formula :  \\ x =  \frac{ - b± \sqrt{ {b}^{2} - 4ac }  }{2a}

define \: a ,b \: and \: c \\ which \: are \: 1, - 3 \: and \:  - 25 \: respectively

t =  \frac{ - ( - 3)± \sqrt{ {( - 3)}^{2} - 4.1. - 25 }  }{2.1}

t =  \frac{  3± \sqrt{ 9    + 100}  }{2}

t = \frac{3 +  \sqrt{ 109 } }{2}

t =  \frac{3  -  \sqrt{ 109 } }{2}

t = 6.7 \\ t =  - 3.7

as \: we \: know \: time \: cannot \: be \: negative

\huge \therefore \: t = 6.7

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3 years ago
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Q is a degree 5 polynomial that passes through the origin, has zeros i and 3 - i, and q( - 2) = - 520. Find
lana66690 [7]
Keirekwkwmsndnsnwowooskssk
6 0
3 years ago
Jane has a 5 × 7-inch photograph that she wants enlarged to a 10 × 14-inch photograph. What is the scale factor from the origina
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I think that the answer is 2, because if you multiply two by each factor in the original photograph then you get the size of the new photograph.
5 0
3 years ago
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