Answer:
½
Step-by-step explanation:
cot(2x) = 1/(tan(2x))
csc(x) = 1/(sin(x))
cot(2x)/csc(x) = sin(x)/tan(2x)
As x --> 0 this fraction is 0/0 which is an indeterminate form.
Using L'Hopital
Derivatives:
sin(x) ---> cos(x)
tan(2x) ---> 2sec²(2x)
cos(x)/(2sec²(2x))
= ½ as x --> 0
A: The other related equations would be:
K = °C + 273.15
K = °F + 457.87
<em>Note: There are other equations that can be related, these are just ones that I find to be related. This is open to interpretation. </em>
B:
23° C + 273.15 = 269.15 K
C:
300 K - 273.15 = 26.85 °C
300 Kelvins is greater than 25 degrees Celsius.
The answer is C
The reason: There are two width and two length sides. So, therefore, if you want the fencing to equal 40 feet around the perimeter, 8 · 2 + L · 2 has to = 40.
You would factor 2 out, and you get 2(8 + L) = 40.
830$ there are 52 weeks in a year. 52 times 15 is 780. 780 plus 50 is 830
For this case we have the following system of equations:
We multiply the first equation by -4:
We have the following equivalent system of equations:
We add the equations:
We find the value of the variable "x":
Thus, the solution of the system is:
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ANswer:
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