To find the x-intercepts algebraically, we let y = 0 y=0 y=0 in the equation and then solve for values of x. In the same manner, to find for y-intercepts algebraically, we let x = 0 x=0 x=0 in the equation and then solve for y.
Vertically opposite angles are always equal.
Given angles are (8x+12)° and (3x+37)°
=> (8x+12)° = (3x + 37)°
=> 8x - 3x = 37-12
=> 5x = 25
=> x = 25/5 = 5°
Angle 1 = (8x+12)° = (8(5)+12) = 40+12 = 52°
Angle 2 = (3x + 37)° = (3(5)+37)° = 15+37 = 52°
Answer:
The height of the ball after 3 secs of dropping is 16 feet.
Step-by-step explanation:
Given:
height from which the ball is dropped = 160 foot
Time = t seconds
Function h(t)=160-16t^2.
To Find:
High will the ball be after 3 seconds = ?
Solution:
Here the time ‘t’ is already given to us as 3 secs.
We also have the relationship between the height and time given to us in the question.
So, to find the height at which the ball will be 3 secs after dropping we have to insert 3 secs in palce of ‘t’ as follows:


h(3)=160-144
h(3)=16
Therefore, the height of the ball after 3 secs of dropping is 16 feet.
Answer:
k=3/5
Step-by-step explanation:
k=y/x
k=3/5