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Rufina [12.5K]
4 years ago
10

Which property is shown? 2.3 + (-1.2 + 9.6) = (2.3+ (-1.2)) + 9.6

Mathematics
1 answer:
abruzzese [7]4 years ago
6 0

Answer:

Associative property of addition

Step-by-step explanation:

A change of grouping is the associative property of addition.

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Answer these please!! :(<br><br> a) 5 + (-4) <br><br> b) -9 + 16 <br><br> c) 10 + (-14)
slamgirl [31]

Answer:

a. 1

b. 7

c. -4

Step-by-step explanation:

a. 5 + (-4)

= 5 - 4

= 1

b. -9 + 16

= 7

c. 10 + (-14)

= 10 - 14

= - 4

If you further explanation how it come then please tell.

6 0
2 years ago
Which expression is equivalent to StartRoot StartFraction 25 x Superscript 9 Baseline y Superscript 3 Baseline Over 64 x Supersc
MAVERICK [17]

Answer:

\displaystyle \frac{5x}{8y^{4}}\sqrt{x}

Step-by-step explanation:

<u>Simplfy in Algebra </u>

We have the following expression

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Simplifying like factors in the denominator and numerator

\displaystyle E=\sqrt{\frac{25x^3}{64y^{8}}}

All the factors are perfect squares except x^3, thus we rewrite:

\displaystyle E=\sqrt{\frac{25xx^2}{64y^{8}}}

Taking the square root of all the perfect square factors:

\boxed{\displaystyle E=\frac{5x}{8y^{4}}\sqrt{x}}

5 0
4 years ago
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Answer:

6048 in     221225582592 in3

Step-by-step explanation:

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3 years ago
Adam tried to compute the average of his 7 test scores. He mistakenly divided the correct sum of all of his test scores by 6, wh
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3 years ago
Give an example of a 2x2 matrix without any real eigenvalues:___________
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Answer:

Step-by-step explanation:

An eigenvalue of n × n is a function of a scalar \lambda  considering that there is a solution (i.e. nontrivial) to an eigenvector x of Ax =  

Suppose the matrix A = \left[\begin{array}{cc}-1&-1\\2&1\\ \end{array}\right]

Thus, the equation of the determinant (A - \lambda1) = 0

This implies that:

\left[\begin{array}{cc}-1-\lambda &-1\\2&1- \lambda\\ \end{array}\right] =0

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Hence, the eigenvalues of the equation are \mathtt{\lambda = i , -i}

Also, the eigenvalues can be said to be complex numbers.

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