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3 years ago

Find the value of the d. 2d - 5 = 17

Mathematics

1 answer:

LenKa [72]3 years ago

6 0

Answer:

d = 11

Step-by-step explanation:

Isolate the variable (d). Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, add 5 to both sides

2d - 5 (+5) = 17 (+5)

2d = 17 + 5

2d = 22

Next, divide 2 from both sides

(2d)/2 = (22)/2

d = 22/2

d = 11

11 is your answer for d.

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FG ∥ CB, A ∈ FG, D ∈ AB, E ∈ AC

andrey2020 [161]

Answer:

The value of x is $31^{\circ}$ .

Step-by-step explanation:

Please look at the figure attached to get more clear solution.

We have given:

FG||CB

And the line that cut the parallel line is transversal so, here BA is transversal

And alternate interior angles on transverse line are equal

So, ∠1=∠4

And ∠4= $28^{\circ}$

Hence, ∠1=∠4= $28^{\circ}$

And On FG the sum of angles will be $180^{\circ}$

∠3+∠2+∠1= $180^{\circ}$

$90^{\circ}$ +∠2+ $28^{\circ}$ = $180^{\circ}$

Hence, ∠2= $62^{\circ}$

Now, we know that the sum of interior angles is equal to the exterior angle:

Therefore, ∠2+∠5=∠6+∠7

$62^{\circ}+3x=x+4x$

On simplification we get:

$2x=62^{\circ}$

$x=31^{\circ}$

Hence, the value of x is $31^{\circ}$ .

3 0

3 years ago

An advertising company designs a campaign to introduce a new product to a metropolitan area of population 3 Million people. Let

Advocard [28]

Answer:

$P(t)=3,000,000-3,000,000e^{0.0138t}$

Step-by-step explanation:

Since P(t) increases at a rate proportional to the number of people still unaware of the product, we have

$P'(t)=K(3,000,000-P(t))$

Since no one was aware of the product at the beginning of the campaign and 50% of the people were aware of the product after 50 days of advertising

We have and ordinary differential equation of first order that we can write

$P'(t)+KP(t)= 3,000,000K$

The <em>integrating factor </em>is

$e^{Kt}$

Multiplying both sides of the equation by the integrating factor

$e^{Kt}P'(t)+e^{Kt}KP(t)= e^{Kt}3,000,000*K$

Hence

$(e^{Kt}P(t))'=3,000,000Ke^{Kt}$

Integrating both sides

$e^{Kt}P(t)=3,000,000K \int e^{Kt}dt +C$

$e^{Kt}P(t)=3,000,000K(\frac{e^{Kt}}{K})+C$

$P(t)=3,000,000+Ce^{-Kt}$

But P(0) = 0, so C = -3,000,000

and P(50) = 1,500,000

$e^{-50K}=\frac{1}{2}\Rightarrow K=-\frac{log(0.5)}{50}=0.0138$

And the equation that models the number of people (in millions) who become aware of the product by time t is

$P(t)=3,000,000-3,000,000e^{0.0138t}$

5 0

4 years ago

Let x = the length of

-BARSIC- [3]

gev me branly for the answer

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Select the correct answer.

jenyasd209 [6]

Answer:

I think it is B it is my guss

4 0

3 years ago

2/5 times 25 help I got game day tomorrow

Alchen [17]

Answer:

Step-by-step explanation:

You are doing:

(2/5) * 25

You can do it two ways, first divide, then multiply, OR multiply, then divide.

In this case, I will multiply, then divide:

First, multiply:

(2 * 25)/5 = (50)/5

Next, divide:

50/5 = 10

10 is your answer.

5 0

3 years ago

Read 2 more answers