Try to make sense out of this problem to where you can understand it
9514 1404 393
Answer:
-5/4 +i(√2)/4 and -5/4 -i(√2)/4
Step-by-step explanation:
I find simplest form to be easier to get to if the leading coefficient is 1. Dividing by 16, we have ...
x^2 +5/2x +27/16 = 0
Completing the square by adding and subtracting the square of half the x-coefficient, we get ...
(x^2 +5/2x +25/16) +27/16 -25/16 = 0
(x +5/4)^2 = 2/16
Subtracting 2/16, taking the square root, and subtracting 5/4 gives ...
x +5/4 = ±√(-2/16)
x = -5/4 ±i(√2)/4
The roots are -5/4 +i(√2)/4 and -5/4 -i(√2)/4.
Answer:
we need to prove : for every integer n>1, the number 
is a multiple of 5.
1) check divisibility for n=1, 
(divisible)
2) Assume that 
is divisible by 5, 
3) Induction,
Now, 
Take out the common factor,
(divisible by 5)
add both the sides by f(k)
We have proved that difference between 
and is divisible by 5.
so, our assumption in step 2 is correct.
Since is divisible by 5, then must be divisible by 5 since we are taking the sum of 2 terms that are divisible by 5.
Therefore, for every integer n>1, the number is a multiple of 5.
X-y=-10
x=-10-y
7x+7y=-14
7(-10-y)+7y=-14
-70-7y+7y=-14
0y=56
y=0
x=-10-y
x=-10-0
x=-10
I’m not 100% sure if this is right, so I hope someone checks this over :)
Y=x+2 solve for x and then reverse labels...
y-2=x so
y=x-2
f^-1(x)=x-2 is the inverse of f(x)=x+2
